if asking for hours to miles (as it looks like in this case, x to y) it would be 1/53
Answer:
its alot to explain but i will try to make it as simple as possible
Step-by-step explanation:
your first goal is to make each problem into the form ax^2+bx+c=0
number 1, 2, 7 and 8 is already done for you
now all you have to do is plug in each number in the standard form into the quadtratic formula.
basically at this point you can just use your calculator to do the rest of the work. dont forget parentheses so it doesnt get confused...
or you can perform the algebraic work.. its all just a matter of plugging in the right numbers into the quadratic formula...
cant really do the work for you since im on my phone. but yeah all you need to do step one is transform each problem into ax^2+bx+c=0 form
then step 2, plug in each number in to the quadtratic formula. from there calculate using basic algebraic rules
1: 5 2: 9 or 10
For question 1 we can round 115 to 100, 5x100 is 500 which is closer to 545 than 7x100 = 700.
Answer: option d is correct .
Step-by-step explanation:
In order to find the same attendance we set both equation equal
8x+191 = -x^2+26x+126
simplifying equation ,we get
x^2 -18x+65=0
(x-5) (x-13) = 0
x =5 or x =13
therefore on 5th day and 13th day both plays attendance is same
and it is obtained by plugging x = 5 in and x =13 in either of the equation.
for x = 5 ,
y = 8(5) +191 = 40+191 = 231
for x = 13
y = 8(13)+191
= 104+191
= 295
therefore option d is correct
