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Reika [66]
3 years ago
13

You are downloading a song. The percent y (in decimal form) of megabytes remaining to download after x seconds is; y=-0.1x+1. If

the equation is; y=-0.1x+1, then how many seconds doe's it take for the download to be 50% complete?
Any opinions help. :)
Mathematics
2 answers:
pychu [463]3 years ago
7 0
Y = -0.1x+1
0.5 = <span>-0.1x+1
-0.5 = -0.1x
x = 5
It takes 5 seconds for the download to be 50% complete.

</span>
soldier1979 [14.2K]3 years ago
6 0
Given :
y = -0.1x + 1
where,
y = percentage,
x = time in seconds
Now, substituting the values from the question into the equation, we get,
         50% = -0.1x +1
      .50 - 1 = -0.1x
          -.50 = -0.1x
-.50 / (-0.1) = x
              5 = x
              x = 5
So, the time taken to download 50% of the song is 5 seconds
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What equation is equivalent to the equation 9x - 13 = 4x + 32
Zigmanuir [339]
I’m guessing if you simplify this it’s gonna be x=6
8 0
2 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Can you guys help please will mark brainliest answer.I need help on 24 and 28
frutty [35]
24) All percents are numbers with the decimal moved 2 to the right. So if you have 275%, move the decimal to the left twice to get a factor of 2.75. that means that the puppy is 2.75 times heavier at 4 months than it was at 2 months. Since you need the answer as a mixed fraction, your answer is;
2.75=2+\frac{3}{4}=2~\frac{3}{4}

28) If 6 of 75 trees are 30+ feet tall and you need to know how many are under, subtract 6 from 75 to get (75 - 6) = 69 trees under 30ft tall.
You're looking for the percent of trees under 30ft tall, so divide the number of trees <30ft by the total number of trees to get;
\frac{69}{75}= .92
Move the decimal 2 to the right to get 92%.
Your answer is that 92% of trees is under 30ft.
3 0
3 years ago
P/5 = 10 what is p
Sav [38]

Answer:

50

Step-by-step explanation:

p/5=10

Your main goal is to isolate p

p/5 = 10, in order to eliminate the 5, multiply 5 on both sides, since it's the inverse of division.

(5)p/5 = 10(5)

p=50

7 0
3 years ago
Construct quadratic equation whose root are -3,+5.show the sloving​
harkovskaia [24]

Answer:

hope this will help u .

plz mark me brainliest

3 0
2 years ago
Read 2 more answers
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