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abruzzese [7]
3 years ago
6

The tallest building in Franklin is two-thirds the

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

The height of tallest building in Franklin is \[\frac{431}{8}\] feet or 53\[\frac{7}{8}\] feet.

Step-by-step explanation:

Given:

The height of tallest building in Mayville is 80\[\frac{13}{16}\] feet or \[\frac{1293}{16}\] feet. (Simplifying the fraction)

And the tallest building in Franklin is 2/3rd of the tallest building in Mayville.

So, multiply the height of Mayville with \[\frac{2}{3}\] to get the height of tallest building in Franklin.

Thus, the height of tallest building in Franklin will be,

h=\[\frac{1293}{16}\]\times\frac{2}{3}\\h=\frac{431}{8}\\h=53\frac{7}{8}

The height of tallest building in Franklin is \[\frac{431}{8}\] feet or 53\[\frac{7}{8}\] feet.

For more details, refer to the link:

brainly.com/question/6201432?referrer=searchResults

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