<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,
As,
Therefore, the vertex at K (-4, 8) is the orthocentre.
Answer:
6
Step-by-step explanation:
To make this easier i like to turn my length into a fraction with the same denominator
36/1= 18/2
18/2 divided by 3/2 equals 6
6 total pieces
Hope this was helpful
Please mark brainliest!
;p
The answer to this question is 7
Answer:
<em>119.0 cm²</em>
Step-by-step explanation:
What is surface area
It is the area of the outside part of anything. Surface area is also called total surface area.
As we can see from the pyramid, it has a square base. How do I know that it is a square base, is by seeing the dimensions of the base, which are 6.4 cm by 6.4 cm in this pyramid. And we already know from basic Geometry that a square has 4 equal sides. So we call it a square pyramid.
So to find the total surface area of this square pyramid, we need the area of the 4 triangular faces and the area of the square base.
So t.s.a of the pyramid = 4 × Area of each triangular face + Area of the square base.
So, total surface area = Area of square base + Area of the four triangular faces.
<em>total surface area</em> = (<em>length²) + (</em>4 × 
× <em>base × height)</em>
<em> t</em><em>otal surface area =</em><em> </em>(6.4 × 6.4) + (4 × × 6.4 × 6.1)
<em>total surface area = 40.96 + 78.08</em>
<em> total surface area = 119.04 cm² ≈ 119.0 cm² (to the nearest tenth) (Answer)</em>
Then the probability is
P(a)+P(b)-P(a&b)
0.5+0.3-0.5*0.3=0.8-0.15=0.65
