Answer:my xbox name is lunabgdrg
Step-by-step explanation:
that is all
5.476 rounded to the hundredths place = 5.48
(2, -1), (6,- 4), and (6, -1). Hope this helps man!
Answer:
8.885
Step-by-step explanation:
Given that :
Sample size, n = 10
The average range, Rbar for all samples = 5
The upper control limit, UCL for the R-chart is :
UCL L= D4Rbar
From the control chart constant table, D4 = 1.777
Hence,
UCL = 1.777 * 5
UCL = 8.885
The UCL for the R-chart is 8.885
Answer:
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