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2 years ago

Calculate the distance between the points C=(-7, 7) and M=(-2, 3) in the coordinate plane.

Mathematics

1 answer:

pishuonlain [190]2 years ago

6 0

Answer:

d = Sqrt 41 = 6.4

Step-by-step explanation:

d = sqrt [(x-x)^2 + (y-y)^2]

d = sqrt [(-7 - - 2)^2 + (7-3)^2]

d = sqrt[(-7+2)^2 + (4)^2]

d = sqrt [(-5)^2 + (4)^2]

d= sqrt (25 + 16)

d = sqrt 41 = 6.4

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Suppose you & your friends are going to the movies.The amount of money you spend for tickets varies directly with the number

mojhsa [17]

This is the equation you need to use: y = kx
So, let's put it this way:
y can be the total amount of money you spend (so $48), and x the number of people (6)

y=kx
48=k*6
k = 48/6
k = 8

The constant variation, and the price of one ticket is 8.

3 0

2 years ago

Which of the following sets include all rational numbers?

kicyunya [14]

It's the Second one and the third one

Step-by-step explanation:

Pie is irrational so you can easily cross it off and it leads to to the second one and the third one

4 0

2 years ago

Need ASAP plz help!! These are the numbers you use. <br>15 27 28 31 34 42 52

Dahasolnce [82]

im sorry but did you ever get the answer?

6 0

2 years ago

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5 % per hour find the bacteria at

Daniel [21]

9514 1404 393

Answer:

5187

Step-by-step explanation:

At the end of 1 hour, the count is 2.5% greater than at the beginning.

5060 + 2.5% × 5060 = 5060 +126.5 = 5186.5

The count at the end of the hour was about 5187.

4 0

2 years ago

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

2 years ago