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OLga [1]
3 years ago
8

Solve 150 + 30

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

i don't know how to do it

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Will give brainliest for answer!!!
Harlamova29_29 [7]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Ten times the square of a non‐zero number is equal to seventy times the number. What is the number?
Nikolay [14]
The original number is 7 i think.
10(x^2) = 70x
10x^2 - 70x = 0
x^2 -7x =0
Δ= b^2 -4ac
where c doesnt exist=0
Δ= 49
-b ± √Δ /2a
7 ± √49 /2
7±7/2
x is either 14/2= 7
or 1/2, which doesnt work.

Lets see:
10(7^2) = 70•7
10•49 = 490
and that is right.

i hope my logic is correct.
5 0
4 years ago
The graph shows the number of text messages sent by
Helen [10]

Answer:

The correct answers are

Night

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5 0
3 years ago
Read 2 more answers
Question 10 What best describes Theoretical Probability? A.) Flipping a coin once to see if it's a heads or tails. B.) Using mat
deff fn [24]

Answer:

B)

Step-by-step explanation:

7 0
3 years ago
PLLLLLSSSS Heeeellppp ill mark brainliest I promisseeeeeeee plsssss
WARRIOR [948]

Answer:

2\,(x-1)^2=4

which is the first option in the list of possible answers.

Step-by-step explanation:

Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:

y=ax^2+bx+c

is at   x_{vertex}=\frac{-b}{2\,a}

For our case, where a=2\,\,, b=-4\,\,,\,\,and \,\,c=-2  we have:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1

And when x = 1, the value of "y" is:

y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4

Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates (x_{vertex},y_{vertex)of the vertex as follows:

y-y_{vertex}=a\,(x-x_{vertex})^2

Then, for our case:

y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4

Then, for the quadratic equal to zero as requested in the problem, we have:

y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4

5 0
3 years ago
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