Question

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a jump discontinuity discontinuous with a point discontinuity

Answer 1

Answer:

$\Large \boxed{\mathrm{discontinuous \ with \ a \ point \ discontinuity}}$

$\rule[225]{225}{2}$

Step-by-step explanation:

$\displaystyle f(x)=\frac{x-3}{x^2-4}$

When x = 2.

We can see that the denominator is equal to 0 when the input value is 2.

$2^2-4=4-4=0$

Obtaining a zero in the denominator indicates a point of discontinuity.

In the graph below, we can see that the function is discontinuous at x = 2.

$\rule[225]{225}{2}$

Answer 2

Answer:

ITS UNDEFINED

Step-by-step explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

ITS UNDEFINED