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kenny6666 [7]
3 years ago
9

for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a ju

mp discontinuity discontinuous with a point discontinuity

Mathematics
2 answers:
Mandarinka [93]3 years ago
6 0

Answer:

\Large \boxed{\mathrm{discontinuous \ with \ a \ point \ discontinuity}}

\rule[225]{225}{2}

Step-by-step explanation:

\displaystyle f(x)=\frac{x-3}{x^2-4}

When x = 2.

We can see that the denominator is equal to 0 when the input value is 2.

2^2-4=4-4=0

Obtaining a zero in the denominator indicates a point of discontinuity.

In the graph below, we can see that the function is discontinuous at x = 2.

\rule[225]{225}{2}

Igoryamba3 years ago
3 0

Answer:

ITS UNDEFINED

Step-by-step explanation:

2-3)/2^2 - 4

-1/(4-4)

-1/0

ITS UNDEFINED

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