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2 years ago

Can someone please calculate the length ?

Mathematics

1 answer:

masya89 [10]2 years ago

5 0

<h3>Answer: 11/20</h3>

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Work Shown:

x = unknown horizontal length

1/5 = 0.2

Perimeter = 2*(width + length)

P = 2*(0.2 + x)

P = 0.4 + 2x

Set this equal to the given perimeter of 1 & 1/2 = 1.5 and solve for x

0.4 + 2x = 1.5

2x = 1.5-0.4

2x = 1.1

x = (1.1)/2

x = 0.55

x = 55/100

x = (5*11)/(5*20)

x = 11/20

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

2 years ago

Jay works as a waiter at a restaurant.

ryzh [129]

Answer:

67.33.

Step-by-step explanation:

To figure out the tip, you need to find 20% of $52.60.

0.2×52.6=10.52

You should leave $10.52 for the waiter if you want to leave him exactly 20%.

To figure the tax, you need to find 8% of $52.60.

0.08×52.6=4.208

Next, add them up:

52.6+10.52+4.208=67.328

The total bill, including tax and tip, will be $67.33.

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1 year ago

How much cheaper per ounce is purchasing 7 ounces for $7.84 compared to purchasing 5 ounces for $5.70

WARRIOR [948]

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2 years ago

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iris [78.8K]

4:3
4 to 3
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2 years ago