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2 years ago

If a triangular road sign has a center height of

Mathematics

1 answer:

Paladinen [302]2 years ago

3 0

Answer:

Formula

A = 1/2 b * h

Substitute

Area = 60 in^2

b = x

h = 2x - 1

60= 1/2 * x * (2x - 1)

Solve

60 = 1/2 * x (2x - 1) Multiply by 2

60 * 2 = x(2x - 1)

120 = x (2x - 1) Remove the brackets.

120 = 2x^2 - x Subtract 120 from both sides.

2x^2 - x - 120 = 0 This factors.

(2x + 15)(x - 8) = 0

Solve for x

2x + 15 = 0

2x = - 15

x = -15/2

x = - 7.5 a negative measurement is useless. Discard this answer.

x - 8 = 0

x = 8

Area (Check)

base = 8

height = 16 - 1 = 15

Area = 1/2 * 8 * 15 = 60 as it should

Answer

Use Area = 1/2 * b * h to find the base and the height.Step-by-step explanation:

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When leaving a town, a car accelerates from 30 kmh-1 to 60 kmh-1 in 5 s. Assuming the

aleksandr82 [10.1K]

Answer:

B .62.5 m

Step-by-step explanation:

convert Kmh-1 in to ms-1

30 Kmh-1 = (30×1000) ÷3600 = 8.3ms-1

60 Kmh-1 = (60×1000) ÷3600 = 16.6 ms-1

acceleration = (16.6 - 8.3) ÷ 5 = 1.66 ms-2

V^2 = U^2 +2aS

(16.6)^2 = (8.3)^2 + 2×1.66 ×S

S = 62.5 m

6 0

3 years ago

How would you find four points using an equation? Use this as an example... y = 40x + 30

Artemon [7]

Plug in random values for x and find y value

assume x = 10 then y = 430

Express as ordered pair:(10,430)

8 0

2 years ago

Can u help me ASAP!!!

Rom4ik [11]

Can be reduced to 1/3

8 0

3 years ago

30 points! Find the angles formed by two intersecting lines, if the sum of three of the four angles is equal to 270°.

nydimaria [60]

Each angle is 90 degrees because 90 times 3 is 270.

8 0

3 years ago

What is the remainder when (3x4 + 2x3 − x2 + 2x − 19) ÷ (x + 2)? 0 5 10 15

Elanso [62]

Answer: Second option is correct.

Explanation:

Since we have given that

$f(x)=3x^4+2x^3-x^2+2x-19$

And $g(x)=x+2$

To find the remainder, we use the Remainder Theorem, which states that when f(x) is divided by (x-c) then the f(c) is the required remainder.

So,

Here, we have,

$x+2=0\\\\x=-2$

So, we will find f(-2) which will give us the required remainder,

$f(-2)=3(-2)^4+2(-2)^3-(-2)^2+2(-2)-19\\\\f(-2)=(3\times 16)-(2\times 8)- 4-4-19\\\\f(-2)=48-16-36-4-19\\\\f(-2)=5$

Hence, Second option is correct.

7 0

3 years ago