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2 years ago

2x(z+4)+1-z+xy; x=4, y=2, z=-3

Mathematics

2 answers:

Marina CMI [18]2 years ago

6 0

Answer:

=20

Step-by-step explanation:

in pic

(hope this helps can I pls have brainlist (crown) ☺️)

Arte-miy333 [17]2 years ago

5 0

$\huge\text{Hey there!}$

<h2> $\large\textsf{2x(z + 4) + 1 - z + xy}$ </h2><h2> $\large\text{= 2(4)(-3 + 4) + 1 - (-3) + 4(2)}$ </h2><h2> $\large\text{= 8(1) + 1 - (-3) + 4(2)}$ </h2><h2> $\large\text{= 8 + 1 - (-3) + 4(2)}$ </h2><h2> $\large\text{= 9 - (-3) + 4(2)}$ </h2><h2> $\large\text{= 12 + 4(2)}$ </h2><h2> $\large\text{= 12 + 8}$ </h2><h2> $\large\text{= 20}$ </h2><h2 /><h3> $\large\boxed{\textsf{Therefore, your answer is: \rm{20}}}\huge\checkmark$ </h3><h3> $\mathsf{Good \ luck \ on \ your \ assignment \ and \ enjoy \ your \ day!}$ </h3><h3 /><h3> $\frak{Amphitrite1040:)}$ </h3>

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2 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

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3 years ago

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vodka [1.7K]

14 2/3 This is the answer! I know you will get this right buddy!

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<h3>What is the percentage?</h3>

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

If everything in a store is 20% off, and the discounted price of an item is $18.00

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Learn more about the percentage here:

brainly.com/question/8011401

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