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ziro4ka [17]
3 years ago
12

Math Help Please?

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
You share only one distribution, so we'll focus on that one:  mean:  30; std. dev.:  4.  

Draw a "standard normal curve."  Draw a vertical line in the exact middle of your curve.  Label this line "30."  Now "one standard dev. above the mean" is 30+4=34; "two std. devs. above the mean is 30+4+4=38, or 30+8=38.  "three std. devs. above the mean is 30+3(4) = 42.  

Now work in the other direction.  Start with the mean:  30.  But now subtract the std. dev. (4) instead of adding it.  You'll get 30-4=26.  This is "1 std. dev. below the mean.  Continue:  find 2 and 3 std. devs. below the mean. 
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4 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

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W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
Kim and Anthony start a dog walking business. During their first week, they paid $10 to make their business cards. Kim walked a
Mekhanik [1.2K]

Answer:

-10$

Step-by-step explanation:

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8 0
3 years ago
Simplify the expression.<br><br> -(10)^-2
valentinak56 [21]

Answer:

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Step-by-step explanation:

-(10)^-2

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We need to make the negative in the exponent positive, which means move it to the denominator

-1

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100

6 0
3 years ago
Read 2 more answers
Type to justify why the two larger triangles are congruent
dexar [7]

Answer:

HL

Step-by-step explanation:

We are dealing with triangle DAB and CBA.

Angles DAB and CBA are right angles making the triangles right triangles.

Side AB is congruent to side BA. That is a leg of each of the two triangles.

Side DB is congruent to side CA. Tat is a leg of each triangle.

The triangles are congruent by HL.

4 0
3 years ago
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