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Hitman42 [59]
3 years ago
8

Que expresiones algebraicas generan la siguiente sucesion 1,4,7,10,13​

Advanced Placement (AP)
1 answer:
morpeh [17]3 years ago
4 0

The arithmetic progression allows to find the algebraic formula of the sequence 1, 4, 7, 10, 13 is:

     aₙ = 3n -2

given parameters

  • Values ​​of the sequence 1, 4, 7, 10, 13

to find

  • Algebraic expression

An arithmetic progression is a sequence of numbers such that the difference between two consecutive numbers is constant.

             a_n - a_{n-1} = d

where aₙ and a_{n-1} are two consecutive terms and d is the ratio between them

in this case

            d = 4 -1 = 3

            d = 7 -4 = 3

            d = 10 - 7 = 3

            d = 13 -10 = 3

so the ratio of the sequence is 3

the first term of the sequence is given

          a₁ = 1

so we can write the general arithmetic progression

          a_n = a_1 + (n-1) d

where aₙ is the nth term, a₁ is the first term, d is the ratio and n is an integer that serves as a counter.

We substitute

           aₙ = 1 + (n-1) 3

           aₙ = 1 + 3n - 3

           aₙ = 3n - 2

Using the arithmetic progression we find the algebraic formula of the given sequence is: aₙ = 3n -2

learn more arithmetic progression here: brainly.com/question/12006170

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2. Solve for x. More than one answer may be correct. Select all correct choices.*
shtirl [24]

Answer:

None of these are correct

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Explanation:

<u><em>Step(i):</em></u>-

Given

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We will apply logarithmic formula

log(a) + log (b) = log a b

  logₓ a = b

⇒   a = xᵇ

<u><em>Step(ii)</em></u>:-

       log^{2} _{10} + log^{(x+5)} _{10} = 2

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<u><em>Final answer:-</em></u>

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<u><em>Verification:-</em></u>

<u><em></em></u>

 log^{2} _{10} + log^{(x+5)} _{10} = 2

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   log^{(100)} _{10} = 2

  log^{(10)^{2} } _{10} = 2

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2 log¹⁰ ₁₀     = 2

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7 0
3 years ago
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