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lapo4ka [179]
3 years ago
10

What is a prime number

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
A prime number is a whole number greater than 1 , whose only two whole number are 1 and itself. The first few prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29. 

Hope this helped you! ^^
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y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.
Elan Coil [88]

General vertex form:

y = m(x − a)² + b  \: with  \: vertex \:  at \:  (a, b)

Given :

y = 2x² + 5x  - 3

Extract "spread factor" m

y = 2( x² +  \frac{5}{2} x) - 3

Complete the square

y = 2(x²  +  \frac{5}{2}x + ( \frac{5}{4})²) - 3

- 2( \frac{5}{4})²

Write as a squared binomial and simplify the constant

y = 2(x +  \frac{5}{4})² - 6 \frac{1}{8}

Re-write to match signs of standard general form:

y = 2(x - ( -  \frac{5}{4}))² \:  + ( - 6 \frac{1}{8})

3 0
2 years ago
IM TIMEDDD HELP!! Which shows a rational number plotted correctly on a number line?
IrinaVladis [17]
I guess the one with 2
6 0
3 years ago
Read 2 more answers
How do I solve 8m+13m>42
choli [55]
8+13=21
so 21m>24
42÷21
m>2
3 0
3 years ago
Read 2 more answers
Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

7 0
3 years ago
Exhibit 6-2 the weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 poun
Evgen [1.6K]
The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.

95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
5 0
3 years ago
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