2x - 2y = 2
2x - 2 x 0 = 2
2x - 0 = 2
2x = 2
x = 1
2x - 2y = 2
2 x 0 - 2y = 2
y = - 1
D.8
A and C are out because they would get you ether lower or equal to 20, which is equal to AC and your trying to find X in AB which is so posed to be the what equals AC+BC.
AB=AC+BC
5x=20+BC
5(8)=20+BC
40=20+BC
40=20+20
AC equals 20. AB will have to equal AC+ CB. If you put in A.4 in AB 5X you will get twenty and that not what you want. You want to get a number that will get you the an answer greater to AC. So 5(8)=40.
Recall: SOHCAHTOA
Sin M = Opp/Hyp
Reference angle = M
Opp = 3√/21
Hyp = 15
Sin M = (3-√21)/15
Sin M = √21/5
Cos M = Adj/Hyp
Reference angle = M
Adj = 6
Hyp = 15
Cos M = 6/15
Cos M = 2/5
Tan M = Opp/Adj
Reference angle = M
Opp = 3√21
Adj = 6
Tan M = (3√21)/6
Tan M = √21/2
:Therefore: Sin M = √21/5
Cos M = 2/5
Tan M = √21/2
