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fgiga [73]
3 years ago
7

To

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

I think it's 56 students have a gadgets

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Write and solve the algebraic inequality: The product of -5 and a number is at least -40.
damaskus [11]
C because that is the only one that make completey since
5 0
3 years ago
Help as soon as possibly
MariettaO [177]

Answer:

see below

Step-by-step explanation:

There are 10 digits

0,1,2,3,4,5,6,7,8,9

Taking the first 6 digits

0,1,2,3,4,5 to represent rain

means that 60 %  or 6/10 digits means rain

This is equal to the chance of rain on the next 5 days

6 0
3 years ago
A bouncy ball is dropped from a height of 16ft and always rebounds of the distance of the previous fall.
nika2105 [10]
16x5=80 cause if it bounces 16 times 5 times then
4 0
2 years ago
Read 2 more answers
A drama club earns $1400 from a production it sells a total of 64 tickets adult tickets and 132 student tickets in adult ticket
Ket [755]

Answer: an adult ticket cost $8 and a student ticket cost $4

Step-by-step explanation:

Let x represent the cost of one student ticket.

Let y represent the cost of one adult ticket.

A drama club earns $1040 from a production. It sells a total of 64 adult tickets and 132 student tickets. It means that

132x + 64y = 1040 - - - - - - - - - -1

An adult ticket costs twice as much as a student ticket. It means that

y = 2x

Substituting y = 2x into equation 1, it becomes

132x + 64 × 2x = 1040

132x + 128x = 1040

260x = 1040

x = 1040/260 = 4

y = 2x = 2 × 4

y = 8

5 0
3 years ago
The ideal width of a safety belt strap for a certain automobile is 6 cm. The actual width can vary by at most 0.45 cm. Write an
OlgaM077 [116]

Answer:

|x-6|\le 0.45

x\in [5.55,6.45]

Step-by-step explanation:

<u>Absolute Value Inequality</u>

Assume the actual width of a safety belt strap for a certain automobile is x. We know the ideal width of the strap is 6 cm. This means the variation from the ideal width is x-6.

Note if x is less than 6, then the variation is negative. We usually don't care about the sign of the variation, just the number. That is why we need to use the absolute value function.

The variation (unsigned) from the ideal width is:

|x-6|

The question requires that the variation is at most 0.45 cm. That poses the inequality:

|x-6|\le 0.45

That is the range of acceptable widths. Let's now solve the inequality.

To solve an inequality for an absolute value less than a positive number N, we write:

-0.45\le x-6 \le 0.45

This is a double inequality than can be easily solved by adding 6 to all the sides.

-0.45+6\le x \le 0.45+6

Operating:

5.55\le x \le 6.45

That is the solution in inequality form. Expressing in interval form:

\boxed{x\in [5.55,6.45]}

3 0
4 years ago
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