Answer:
We have:
x < 4 AND x > a.
if a = 4 and we use an "or" instead of the "and" we have:
x < 4 or x > 4.
This is:
"x is larger than 4 or smaller than 4."
Then the solution of this is all the real numbers except the value x = 4.
The set of solutions can be written as:
{xI x ∈ R \ [4]}
Where this reads:
"x belongs to the set of the reals minus the number 4".
Or we also could write it as:
x ∈ (-∞, 4) ∪ (4, ∞)
Where we have two open ends in the "4" side, so the value x = 4 does not belong to that set.
Answer:
8*2^(n-1)
Step-by-step explanation:
This is a geometric sequence since we multiply from the previous term.
a_n = a_1 * common ratio^(n-1) where a_n is the nth number and a_1 is the first.
The first term is 8, so we have
a_n = 8*<common ratio>^(n-1) = 8*2^(n-1)
Answer:
I believe its B, But I am unsure since I haven't done geometry in a couple years.
Answer:
If the signs are different subtract the smaller absolute value from the larger absolute value.
Answer:
B. x = -8
Step-by-step explanation:
-4(2x + 3) = 2x + 6 - (8x + 2)
-8x -12 = 2x + 6 - 8x -2
(now, "-8" in both terms is cancelled):
-12 = 2x + 6 - 2
(leave 2x alone in second term):
-12 -6 +2 = 2x
-16 = 2x
-16/2 = x
-8 = x
