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3 years ago

LINE PERPENDICULAR TO Y=1/5X+5 WITH THE POINT (-6,0)?????

2 answers:

4 0

<span>y=1/5x+5 with the point (-6, 0)

The line perpendicular to this line will have a slope that's the negative reciprocal of this one. So if the slope here is 1/5 (based on y=mx+b, where m is the slope), then the perpendicular slope would be -5/1.

So now that you have the point and the slope, use the point-slope formula.
y - y</span>₁ = m(x - x₁)
m = -5
(x₁, y₁) = (-6, 0)

y - 0 = -5(x + 6)
y = -5x - 30

y = -5x - 30 is the line perpendicular to y=1/5x+5.

EastWind [94]3 years ago

3 0

You need to flip the slope (or number in front of the x) and sign of it to do the perpendicular part. This should give you: y=-5x+b. Now put the -6 in for the x, and the 0 in for the y. Simply solve for an answer of -30=b. Your final answer is: y=-5x-30

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2 years ago

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I’m confused on this one

eduard

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2 years ago

dana is flying a kite whose string is 65 meters long and makes a 70 degree angle with the ground. How far is the kite above the

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3 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

How to solve 10m-2/5=48/5

Romashka [77]

Answer:

Step-by-step explanation:

10m-2/5=9 and 3/5

10m-2/5=9.6 (where 9 and 3/5 is equal to 9.6)

50m-2=48 (i multiplied 10m by 5 and 9.6 by 5)

50m=50 ( i added 2 to both sides)

m=1 ( i divided by 50 to both sides to find m)

5 0

3 years ago