Answer:
13 and 16
Step-by-step explanation:
let the 2 parts be x and y, then
x + y = 29 → (1) and
x² + y² = 425 → (2)
From (1) → x = 29 - y → (3)
substitute x = 29 - y into (2)
(29 - y)² + y² = 425 ( expand factor )
841 - 58y + y² + y² = 425 ( rearrange into standard form )
2y² - 58y + 416 = 0 ← in standard quadratic form
divide all terms by 2
y² - 29y + 208 = 0
Consider the factors of 208 which sum to - 29
These are - 13 and - 16, hence
(y - 13)(y - 16) = 0
equate each factor to zero and solve for y
y - 13 = 0 ⇒ y = 13
y - 16 = 0 ⇒ y = 16
substitute these values into (3)
x = 29 - 13 = 16 and x = 29 - 16 = 13
The 2 parts are 13 and 16
First you collect the like term then variable one side coefficient one side and constant
Answer: x=−10
Step-by-step explanation:
x−3−2(x+6)=−5
x+−3+(−2)(x)+(−2)(6)=−5(Distribute)
x+−3+−2x+−12=−5
(x+−2x)+(−3+−12)=−5(Combine Like Terms)
−x+−15=−5
−x−15=−5
−x−15+15=−5+15
−x=10
Answer:
5.25
Step-by-step explanation:
