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Arturiano [62]
3 years ago
14

Explain why figure b is not the image of figure a after a reflection using line l

Mathematics
2 answers:
Kaylis [27]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

Figure A has a square cut out into it as figure B has a trapezoid cut out into it.

A reflection is mirroring an image, this means that the image must be identical to its reflected image.

Because figure A and B have different shapes cut into it they are not identical and can therefore not be reflections.

Karolina [17]3 years ago
5 0
I have the same answer ^^
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Which expression is equivalent to the given expression? Assume the denominator does not equal zero.
ipn [44]

The expression equivalent to given expression is \frac{b^4}{a}

<em><u>Solution:</u></em>

Given expression is:

\frac{a^3b^5}{a^4b}

We are asked to find the expression equivalent to given expression

Assume that denominator does not equal to zero

We can apply the exponent rule in given expression

\frac{x^a}{x^b} = x^{a - b}

Apply the above rule in given expression

\frac{a^3b^5}{a^4b} = a^{3-4} \times b^{5-1} = a^{-1}b^4

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3 years ago
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umka21 [38]

Answer:

A. 6 sq. units

Step-by-step explanation:

Area of a triangle can be found with base times height divided by 2

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3 years ago
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VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

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Solve by substitution <br> x - 2y = 10<br> 1/2x - 2y = 4
mars1129 [50]

Answer:

ypu can do this by using this please vote

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3 years ago
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