We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect population,

$\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100$

$\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100$

$\text{Growth percentage}=\frac{\text{10}}{20} \cdot100$

$\text{Growth percentage}=0.5 \cdot100=50$

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

$P(w)=20(1+0.50)^{w}$ , where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

$P(11)=20(1+0.50)^{11}$

$P(11)=20(1.50)^{11}$

$P(11)=20\cdot 86.49755859375$

$P(11)=1729.951171875\approx 1730$

Therefore, population of insects at the end of 11th week will be 1730.

7 0

3 years ago

Write the equation of the line that passes through the points (-3, -2) and (0, -3)

Lady bird [3.3K]

Answer:

y= -1/3x -3

Step-by-step Explanation:

3 0

2 years ago

Read 2 more answers