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3 years ago

Which of the following represents (Picture provided)

Mathematics

2 answers:

nikdorinn [45]3 years ago

7 0

Answer:

b. $(1,6]$

Step-by-step explanation:

The given inequality is $1\:$ .

We use the parenthesis $()$ to represent an open interval < or >.

We use the square brackets $[]$ to represent a closed interval $\le$ or $\ge$ .

$1\:$ represents $(1,6]$ .

The correct choice is B.

Amiraneli [1.4K]3 years ago

4 0

Answer:

Step-by-step explanation:

You are given the double inequality

$1$

This means that x is greater than 1 and less than or equal to 6.

Thus, point 1 must be excluded (with bracket "(") and 6 must be included (with bracket "]").

Hence, the correct answer is $(1,6].$

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Which of the following is a polynomial A.x^2+2 B.(x^8-2)/(x^-2+3) C. 7x^7-2x^-4+3 D.x^x-1

EastWind [94]

A. x²+2 - a polynomial
B.(x⁸-2)/(x⁻²+3) rational function
C. 7x⁷-2x⁻⁴+3 (It has negative value of exponent, so it cannot be a polynomial.)
D.x^x-1 (x is an exponent it cannot be a polynomial)

6 0

3 years ago

Help me for free Brainliest

vaieri [72.5K]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

Read 2 more answers

Paula and Kawai shared $312 in the ratio of 6:7. How much money did each person get?

Maslowich

Answer:

Paula get $\$144$ and Kawai get $\$168$ .

Step-by-step explanation:

Given: Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

To find: How much money did each person get?

Solution:

We have,

Paula and Kawai shared $\$312$ in the ratio of $6:7$ .

So, let Paula get $\$6x$ and Kawai get $\$7x$ .

As per the question,

$6x+7x=312$

$\implies13x=312$

$\implies x=\frac{312}{13} =24$

Therefore, Paula get $6\times 24=\$144$ , and Kawai get $7\times 24=\$168$ .

Hence, Paula get $\$144$ and Kawai get $\$168$ .

6 0

2 years ago

Identify a and b in the binomial expression (2x3 + 3y2)7.

Shkiper50 [21]

$\text{Hey there!}$

$\text{Distribute the value of 7 in each of your terms}$

$\text{(2x}^3+\text{3y}^2)(7)$

$\text{2x}^3\times7=\text{14x}^3$

$\text{3y}^2\times7=\text{21y}^2$

$\text{We cannot combine like terms because they AREN'T any in this equation}$

$\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

8 0

3 years ago

Read 2 more answers

What is the abscissa of the midpoint of the line segment whose endpoints are (5√2,2√3) and (√2,2√3)

xxMikexx [17]

Let
A------> (5√2,2√3)
B------> (√2,2√3)

we know that
the abscissa and the ordinate are respectively the first and second coordinate of a point in a coordinate system
the abscissa is the coordinate x

step 1
find the midpoint
ABx------> midpoint AB in the coordinate x
ABy------> midpoint AB in the coordinate y

ABx=[5√2+√2]/2------> 6√2/2-----> 3√2
ABy=[2√3+2√3]/2------> 4√3/2-----> 2√3

the midpoint AB is (3√2,2√3)

the answer is
the abscissa of the midpoint of the line segment is 3√2

see the attached figure

3 0

2 years ago

Read 2 more answers