A student organization sells shirts to raise money for events and activities. The

Mr. Lucas baked 25 cookies. 3 fifths of the cookies were oatmeal. How many oatmeal cookies did Mr. Lucas bake?

My name is Ann [436]

Answer:18 oatmeal cookies.

Step-by-step explanation:

4 0

3 years ago

Change 3240 degrees/second to radians/second

Sergeu [11.5K]

Using the formula 1° × π/180 = 0.01745rad,

3240 degrees/second = 56.54867 radians/seconds

4 0

3 years ago

Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.

vesna_86 [32]

Factorize the denominator:

$\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}$

If $x\neq\pm2$ , we can cancel the factors of $x^2-4$ , which makes $x=-2$ and $x=2$ removable discontinuities that appear as holes in the plot of $g(x)$ .

We're then left with

$\dfrac1{x+1}$

which is undefined when $x=-1$ , so this is the site of a vertical asymptote.

As $x$ gets arbitrarily large in magnitude, we find

$\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0$

since the degree of the denominator (3) is greater than the degree of the numerator (2). So $y=0$ is a horizontal asymptote.

Intercepts occur where $g(x)=0$ ( $x$ -intercepts) and the value of $g(x)$ when $x=0$ ( $y$ -intercept). There are no $x$ -intercepts because $\dfrac1{x+1}$ is never 0. On the other hand,

$g(0)=\dfrac{0-4}{0+0-0-4}=1$

so there is one $y$ -intercept at (0, 1).

The domain of $g(x)$ is the set of values that $x$ can take on for which $g(x)$ exists. We've already shown that $x$ can't be -2, 2, or -1, so the domain is the set

$\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}$

8 0

3 years ago

What are considered measures of variability

shusha [124]

Statisticians use summary measures to describe the amount of variability or spread in a set of data. The most common measures of variability are the range, theinterquartile range (IQR), variance, and standard deviation. This is from google btw

7 0

3 years ago

WILL MARK BRAINLIEST!!! Can someone help me wit des questions? (SHOW UR WORK)

spayn [35]

1) -3x -3 -7x = 17
• start by grouping so add -3x and -7x which gives you -10x
• 10x -3 (+3) = 17 +3 = 20 add 3 on both sides)
• 10x (/10) = 20/ 10 = 2
1) x = 2

2) 10x -6 (+6) = 24 + 6 = 30
• 10x (/10) = 30/ 10 = 3
2) x = 3

3) -4 (+4) -5x = -39 +4 = -35
• -5x (/-5) = -35/ -5 = 7
3) x = 7

4) 3x - 5 > 10
this one i don’t understand, is there a typo maybe ?

5) -5x + x + 16 = -3 you can put a 1 to hold the place of x to make it 1x
• (-5x + 1x) + 16 = -3
• -4x + 16 (-16) = -3 -16 = -19
• -4x (/-4) = -19/ -4 = 4.75 or 4 3/4
5) x = 4.75

6 0

3 years ago