Answer:
<em>x - 3y = 6</em>
Step-by-step explanation:
<u>Equation of the line in intercept form</u>
The intercept form of the equation of a line is:
Where:
a = x-intercept
b = y-intercept
The standard form of a line is:
Ax + By = C
The given line has a=6 and b=-2, thus:
Multiplying by 6:
x - 3y = 6
This is the required standard form of the line.
Thus, the standard form of the line is:
x - 3y = 6
Answer:
see explanation
Step-by-step explanation:
15
JK + KL = JL , substitute values
2x + 1 + 6x = 81, that is
8x + 1 = 81 ( subtract 1 from both sides )
8x = 80 ( divide both sides by 8 )
x = 10
Thus JK = 2x + 2 = 2(10) + 1 = 20 + 1 = 21
KL = 6x = 6 × 10 = 60
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16
JK + KL = JL , substitute values
2x + x + 2 = 5x - 10 , that is
3x + 2 = 5x - 10 ( subtract 3x from both sides )
2 = 2x - 10 ( add 10 to both sides )
12 = 2x ( divide both sides by 2 )
6 = x
Thus
JK = 2X = 2 × 6 = 12
KL = x + 2 = 6 + 2 = 8
JL = 5x - 10 = 5(6) - 10 = 30 - 10 = 20
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17
Calculate the distance d using the distance formula
d =
with (x₁, y₁ ) = S(7, 3) and (x₂, y₂ ) = T(1, - 5)
d =
=
=
= = 10