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3 years ago

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Mathematics

1 answer:

padilas [110]3 years ago

3 0

Answer:

This is in order! first to last column! Type it in this order from right to left!

Flour cups= 3, 30, 18, 6, and 24

Sugar cups= 2, 20, 12, 4, and 16

Cookies= 12, 120, 72, 24, and 108

Step-by-step explanation:

If you look up and down, there are one or two boxes missing except for the middle one. The middle one has 18 flour, 12 sugar, and 72 cookies. so for 72 cookies, it contains 18 flour and 12 sugar. so 18:12 is in 72 cookies. if we want to find out how many are in 3 flour, we have to get 18 to 3. so we do /6=3. so we divide everything in that 72 equation by 6. 18/6=3. 12/6=2. 72/6=12.

for the first column, we have 3 flour, 2 sugar, and 12 cookies. then we fill in the rest.

second column: is 10x what the first column is so we multiply everything by ten. 3x10=30. 2x10=20. 12x10=120

third column= we already have the answer

fourth column= two times the first column so we multiply by two. 3x2=6. 2x2=4. 12x2=24

fifth column= 8 times the first column so we mulitply by eight. 3x8=24. 2x8=16. 12x8=108

----------------------END OF SCRIPT. PLEASE MARK ME BRAINLIEST-----------------

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Tamaica can wrap 24 presents in 5 hours. how long will it take her to wrap 72 presents?

soldi70 [24.7K]

So for this you will be doing proportions, and in this case the equation will be $\frac{24}{5} =\frac{72}{x}$

Firstly, you will cross multiply. Your equation should look like this: $24x=360$

After that, just divide 24 on each side and your answer will be $x=15$

In short, she can wrap 72 presents in 15 hours.

7 0

3 years ago

Read 2 more answers

An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and

lana [24]

Answer:

Option D. 10,779 feet

Step-by-step explanation:

Given from the figure attached,

PT = OB = 7000 ft

PB = OT = x feet

and angle of elevation (∠POT) = 30°

By applying Tan rule in the triangle POT,

tan33° = $\frac{\text{Opposite side}}{\text{Adjacent side}}$ = $\frac{PT}{OT}$

tan33° = $\frac{7000}{x}$

x = $\frac{7000}{\text{tan}33}$

x = 10779 feet

Therefore, distance between the bird (B) and plane (P) is 10,779 feet.

Option D. will be the answer.

3 0

3 years ago

Someone please hurry and help with these its ok if its wrong will do brainliest sorry its blurry but please try!!!!

arlik [135]

Step-by-step explanation:

the slope is always the factor of x.

it is expressed as ratio y/x indicating how many units y changes when x changes a certain amount of units.

parallel means they have the same slope (factor of x).

perpendicular (90 degrees) means x and y trade places upside-down, and the sign is flipped.

so,

10) neither. we have the slopes -2/1 and 1/1.

11) parallel. the slopes -1/2 and -1/2.

12) perpendicular. the slopes 5/1 and -1/5.

16) parallel. special case. all points that have x=4 and x=2. these are 2 vertical lines (parallel to the y-axis also known as x=0).

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3 years ago

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I have a sum of 159, and difference of 3 .What are the 2 numbers?

Lemur [1.5K]

$x+y=159\\
\underline{x-y=3}\\
2x=162\\
x=81\\\\
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These numbers are 81 and 78.

7 0

3 years ago

textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year old

Butoxors [25]

Testing the hypothesis, we have that:

The null hypothesis is: $H_0: \mu = 128$

The alternative hypothesis is: $H_1: \mu \neq 128$

b) The p-value of the test is of 0.1212.

c) Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

d) Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item a:

At the null hypothesis, we test if the mean is the same, that is, of 128 texts every day, hence:

$H_0: \mu = 128$

At the alternative hypothesis, we test if the mean is different, that is, different of 128 texts every day, hence:

$H_1: \mu \neq 128$

Item b:

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the population.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 118.6, \mu = 128, \sigma = 33.17, n = 30$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{118.6 - 128}{\frac{33.17}{\sqrt{30}}}$

$z = -1.55$

Since we have a two-tailed test, as we are testing if the mean is different of a value, the p-value is P(|z| < 1.55), which is 2 multiplied by the p-value of z = -1.55.

Looking at the z-table, z = -1.55 has a p-value of 0.0606

2(0.0606) = 0.1212

The p-value of the test is of 0.1212.

Item c:

Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item d:

Using a z-distribution calculator, the critical value for a two-tailed test with 95% confidence level is |z| = 1.96.

Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

A similar problem is given at brainly.com/question/25369247

4 0

3 years ago

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