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Fynjy0 [20]
2 years ago
11

Will give brainliest

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

Answer: 45 Degrees

Step-by-step explanation:

You might be interested in
RS = 4x – 9, ST = 19, RT = 80 – 14<br><br> Equation:<br><br> 82 – 14<br><br> RS<br><br> RT
algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

4 0
3 years ago
Three fourths of a number p less than two is five sixths of another number r plus five solve for r
maw [93]
r = -3/4p - 18/5 
(or you could put 3.6 or 3 3/5 instead of 18/5)

2 - 3/4p = 5/6r + 5 
-5                     -5
-3 - 3/4p = 5/6r
 /(5/6)       /(5/6) 
-18/5 - 3/4p = r 
-3/4p - 18/5 = r 

5 0
3 years ago
A number greater than 40 whose prime factorization contains 3 prime numbers that do not repeat
Tomtit [17]
That is true because factors of 40 are 10,5
5 0
2 years ago
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the graph of the g
krok68 [10]

Answer:

Step-by-step explanation:

The slope of the line is m = -5

4 is your x1

-3 is your y1

Plug into the equation y - y1 = m(x - x1)

y + 3 = -5(x - 4)

y + 3 = -5x + 20

   -3             -3

y = -5x + 17

3 0
3 years ago
Solve each of the following systems of equations by substitution
Delvig [45]

Answer:

1) The solution to the given equations is (3,6)

2) The solution to the given equations is (7,-1)

3) The solution to the given equations is (6,5)

Step-by-step explanation:

1) Given equations are x+y=5\hfill (1)

and x=1+y\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=1+y

Substitute the value of x=1+y  in equation (1) we get

(1+y)+y=5

1+y+y=5

1+2y=5

2y=5-1

2y=4

y=\frac{4}{2}

Therefore y=2

Now substitute the value of y=2 in equation (2) we get

x=1+y

x=1+2

Therefore x=3

The solution is (3,6)

2) Given equations are 2x+3y=11\hfill (1)

and x+y=6\hfill (2)

To solve the given equations by substitution method :

From equation (2) we have the value x=6-y

Substitute the value of x=6-y  in equation (1) we get

2(6-y)+3y=11

12-2y+3y=11

y=11-12

Therefore y=-1

Now substitute the value of y=-1 in equation (2) we get

x+(-1)=6

x=6+1

Therefore x=7

The solution is (7,-1)

3) Given equations are x-y=1\hfill (1)

and 6x-7y=1\hfill (2)

To solve the given equations by substitution method :

From equation (1) we have the value x=1+y

Substitute the value of x=1+y  in equation (2) we get

6(1+y)-7y=1

6+6y-7y=1

-y=1-6

Therefore y=5

Now substitute the value of y=5 in equation (1) we get

x-5=1

x=1+5

Therefore x=6

The solution is (6,5)

8 0
3 years ago
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