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Inessa05 [86]
3 years ago
14

Based on what we established about the classification of x and using the closure of integers, what does the equation tell you ab

out the type of number x must be for the sum to be rational? What conclusion can you now make about the result of adding a rational and an irrational number?
Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

Step-by-step explanation:

Hatshy [7]3 years ago
3 0

Answer:   The product of a rational number with an irrational number is an irrational number. To see this assume that x is a rational number and y an irrational number. Then let us assume that the product xy is rational, which means that there are integers a,b such that xy=a/b. But then we obtain y=(1/x)(a/b) which is also rational since the set of rational numbers is closed under multiplication. But this is a contradiction since y was assumed to be an irrational number.  

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sashaice [31]

Answer:

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Match each statement to the reasons given for the geometric proof.
Savatey [412]

Answer:  5, 3, 1, 2, 6, 4

<u>Step-by-step explanation:</u>

The proof should be written as follows (which is a different order than provided):

  <u>Statement                       </u>                         <u>Reason                                         </u>

1. ABCD is a parallelogram                     1. Given

2. AB||DC and AD||BC and AB ≅ DC     2. Definition of parallelogram

3. ∠ABD ≅ ∠CDB                                    3. Alternate Interior Angles Theorem

4. ∠DEC ≅ ∠BEA                                     4. Vertical Angles Theorem

5. ΔABE ≅ ΔCDE                                    5. AAS Congruency Theorem

6. AE = CE and BE = DE                         6. CPCTC

This is the order provided in your question:

5. ΔABE ≅ ΔCDE                                    5. AAS Congruency Theorem

3. ∠ABD ≅ ∠CDB                                    3. Alternate Interior Angles Theorem

1. ABCD is a parallelogram                     1. Given

2. AB||DC and AD||BC and AB ≅ DC     2. Definition of parallelogram

6. AE = CE and BE = DE                         6. CPCTC

4. ∠DEC ≅ ∠BEA                                     4. Vertical Angles Theorem

5 0
3 years ago
Figure ABCDE has vertices A(−2, 3), B(2, 3), C(5, −2), D(0, −4), and E(−2, −2). Plot the points on your own coordinate grid and
Anastasy [175]

There's a right angle that they want you to make a rectangle out of.  I'm ignoring that and using each of the five sides to make a triangle with the origin.

A.  Five triangles, zero rectangles.

B.

AB=4, the difference of the x coordinates since the y coordinates are the same

AE = 5, the difference in the y coordinates since the x coordinates are the same

C.  We'll use the Shoelace Formula, adding up all those triangles I made.  A triangle with vertices (0,0), (a,b), (c,d) has signed area A = (1/2)(ad-bc).  We go around counterclockwise so they all have positive areas, starting with AE, then ED, DC, CB, BA.

Area = (1/2) (  (-2)(-2) - 3(-2)  +  (-2)(-4) - (-2)(0)  +  0(-2) - (-4)(5)  + 5(3) - (-2)(2) + 2(3) - (3)(-2))

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lutik1710 [3]

Step-by-step explanation:

14 ft

is your answer please mark as brilliant

i

6 0
3 years ago
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