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liubo4ka [24]
2 years ago
11

In triangle ABC, a=31 , b=22 , c=18. Identify m∠A rounded to the nearest degree.

Mathematics
1 answer:
Veronika [31]2 years ago
8 0

Answer:

101

Step-by-step explanation:

According to the Law of Cosines, for any △ABC with side lengths a, b, and c, a2=b2+c2−2bccosA; b2=a2+c2−2accosB; and c2=a2+b2−2abcosC

.

The Law of Cosines can be used because all three side lentghs are known.

Set up the equation for the Law of Cosines:

a2=b2+c2−2bccosA

Substitute the known values into the Law of Cosines:

312=222+182−2(22)(18)cosA

Square the values and multiply:

961=484+324−792cosA

Add:

961=808−792cosA

Subtract 808

from both sides:

153=−792cosA

Divide both sides by −792

:

153−792=cosA

According to this equation m∠A

is equal to the inverse cosine function of −153792

. Write this:

m∠A=cos−1(−153792)

Calculate the value of the inverse cosine −153792

on a calculator:

m∠A≈101°

Therefore, m∠A≈101°

.

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Answer:

\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}

Step-by-step explanation:

A. Scale factor

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\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}

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If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}

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Answer:

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So, we calculate the probability from 0 to 3:

 p (x = 0) = 2.72 ^ (- 4.33) * 4.33 ^ (0) / 0! = 0.01313

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Answer:

7/9

.......

......

......

7 0
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