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Ostrovityanka [42]
2 years ago
6

Un árbol de 4.8 m de altura proyecta una sombra de 6.3 m. Encuentra la medida del ángulo "x" de elevación del sol.

Mathematics
1 answer:
Semenov [28]2 years ago
7 0

Answer:

37 degrees

Step-by-step explanation:

Tan x = 4.8/6.3

Tan x = 0.76

Tan^-1 (0.76) = 37 degrees

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bring the lines side by side ( example || )

Step-by-step explanation:

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Given: -16 = m/5 -18; <br> Prove: m=10
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311 students went on a field trip. Six buses were
kow [346]

Answer:

50.6

Step-by-step explanation:

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2 years ago
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A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
Please help Math question 50 points! An employer provides two payment options for employees. Option A: Receive $200 the first we
dezoksy [38]

Answer:

it could be and to show his number two because it's running all those numbers up over and over again by percentage is that the end is going to give you a big number

Step-by-step explanation:

on the beginning is adding 200 + 50 we should give you 250 then is a 200 more so it was equals to 450 but then he asked you per week you get 50 extra so is basically 50 x 6 cylinder 6 weeks and I will give you a promise off $300 $300 + 450 equals to 750 each week is 10% so is basically equals to 50 so 50 + 50 + 50 + 50 or the easiest way is 50 * 6 I would go with answer to like I said because it's showing like a little of of a conversation was not given in any Solution on a specific number and that's the most closest one to like the whole problem

3 0
2 years ago
Read 2 more answers
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