<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
B and C for the first two
Answer: 6 and 1/4
Step-by-step explanation: To solve this problem, we first leave 5/2 alone so don't do anything to it.
For our second fraction, we want to switch the numerator and the
denominator which means find the reciprocal of it.
The reciprocal of 2/5 is just the opposite of it when
you flip it and it's going to be 5/2.
Because we did the opposite there, we need to do the opposite
of division and the opposite of division is multiplication.
So now we have 5/2 × 5/2 which is 25/4 or 6 and 1/4.
1 cm is the base of the triangle
The answer you put in is y = 1/2 + 4
