3 years ago

Write an expression that represents the perimeter of the figure below. Write your

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

5 0

Answer:

start by answering the question

Step-by-step explanation:

the answer is in the top right

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tamaranim1 [39]

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3 years ago

You wish to take flying lessons. The introductory course cost $125 per session and will include 12 lessons. Smith Flying Academy

allsm [11]

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3 years ago

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

ladessa [460]

9514 1404 393

Answer:

opposite: 4.88
adjacent: 14.18

Step-by-step explanation:

SOH CAH TOA is a mnemonic intended to remind you of the relevant trig relations.

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Cos = Adjacent/Hypotenuse ⇒ adjacent = 15×cos(19°) ≈ 14.18 units

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3 years ago

Abc is an equilateral triangle and has an area of 8/5. point d is the midpoint of side ab, point e is the midpoint of side bc, a

nlexa [21]

Hello,

There are 4 congurent equilateral triangles in ABC and each has an area of (8/5)/4=2/5.
To form the parallelogram we need 2 triangles: 2* 4/5=4/5.

Answer C.

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3 years ago

if you draw two right triangles using the line as the hypotenuse, do the triangles have to be similar? Why or why not?

diamong [38]

Answer:

All the right triangles will be similar.

Step-by-step explanation:

See the attached diagram.

Let us assume any two right triangles are drawn on the line OP, and AB and A'B' as the hypotenuse on the same line OP.

Since the slope of the line OP is constant and assume that it makes x° with the positive x-axis.

Hence, $\tan x = \frac{AC}{BC} = \frac{A'C'}{B'C'}$

⇒ $\frac{AC}{A'C'} = \frac{BC}{B'C'}$

Therefore, the sides of the two right triangles are in the same ratio and hence, Δ ABC and Δ A'B'C' are similar.

Hence, all the right triangles will be similar. (Answer)

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3 years ago