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3 years ago

Help ASAP please! Thanks in advance.

Mathematics

1 answer:

ASHA 777 [7]3 years ago

7 0

Step-by-step explanation:

The second one, of course. Because the inequality means that x must be smaller than -3. So in negative numbers, numbers are getting smaller when they go far from 0. So $-8\frac{2}{3},-6,-4, -3,5$ are smaller than -3 because the distance between 0 and these numbers are more than he distance between zero and -3. Good luck :)

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Pls answer ASAP I will give brainliest answer.

quester [9]

The answer would be 9.45

4 0

3 years ago

Read 2 more answers

Martha wrote an example of a quadratic function for a homework assignment. The function she wrote is shown. f(x) = 5x3 + 2x2 + 7

larisa86 [58]

Answer:

The two correct options are:

The first term, 5x³, can be eliminated

The exponent on the first term, 5x³, can be changed to 2 and then combined with the second term, 2x²

Explanation:

The degree of an expression is given based on the highest power in the expression

The given expression is:

5x³ + 2x² + 7x - 3

We can note that the highest power in the given expression is 3 which means that the degree of the expression is 3

A quadratic function is a function of degree 2. This means that the highest degree in the expression (function) must be 2

Accordingly, Martha should get rid of the term with power 3 (5x³) in her equation

This can be done by 2 methods:

1- She simply eliminates the term with the third degree

2- She changes the degree of the term with degree 3 to a lower degree and combines it with any existent like term

Comparing the above with the given options, we can conclude that the two correct options are:

- The first term, 5x³, can be eliminated

- The exponent on the first term, 5x³, can be changed to 2 and then combined with the second term, 2x²

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

2 years ago

Y = f(x) + 3 describe the functions that take place

hram777 [196]

Answer:

A function can be reflected about an axis by multiplying by negative one. To reflect about the y-axis, multiply every x by -1 to get -x. To reflect about the x-axis, multiply f(x) by -1 to get -f(x).

Step-by-step explanation:

8 0

3 years ago

Solve sec2theta + tantheta - 3 =0 for 0

Serhud [2]

Answer:

Ф = $\frac{\pi }{4} ,\frac{5\pi}{4}$

Step-by-step explanation:

It is a bit difficult to input the work here, so I uploaded an image

First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
Then we can combine like terms
Then we can factor this as a polynomial function
Then we can set each term equal to zero and solve for Ф
The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
The second term tan(Ф) - 1 = 0 has two solutions of $\frac{\pi}{4}$ and $\frac{5\pi}{4}$ so these are the solutions to the problem

7 0

3 years ago