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2 years ago

Identify at least one pair of the following angles

Mathematics

2 answers:

Dahasolnce [82]2 years ago

3 0

Answer:

Alternate exterior angles : ∠g = ∠b , ∠h = ∠a (opposite sides and on outer side)

Alternate interior angles : ∠c = ∠f , ∠e = ∠d (opposite sides and on inner side)

Consecutive interior angles : ∠c = ∠e , ∠d = ∠f (same sides and on same line)

Corresponding angles : ∠e = ∠a, ∠f = ∠b, ∠g = ∠c, ∠h = ∠d (same sides on the line)

Linear pairs : ∠c and ∠e, ∠d = ∠f, (they add to 180)

Vertical angles : ∠c =∠b, ∠d = ∠a, ∠g=∠f, ∠e = ∠h (vertical angles)

Viktor [21]2 years ago

3 0

Answer:

Source: Maimuna

Alternate exterior angles : ∠g = ∠b , ∠h = ∠a (opposite sides and on outer side)

Alternate interior angles : ∠c = ∠f , ∠e = ∠d (opposite sides and on inner side)

Consecutive interior angles : ∠c = ∠e , ∠d = ∠f (same sides and on same line)

Corresponding angles : ∠e = ∠a, ∠f = ∠b, ∠g = ∠c, ∠h = ∠d (same sides on the line)

Linear pairs : ∠c and ∠e, ∠d = ∠f, (they add to 180)

Vertical angles : ∠c =∠b, ∠d = ∠a, ∠g=∠f, ∠e = ∠h (vertical angles)

Step-by-step explanation:

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2 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

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2 years ago

Read 2 more answers

Write 0.614¯¯¯ as a fraction in simplest form.

Verizon [17]

Answer:

307/500

Step-by-step explanation:

307 is a prime number.

The way to find this out is to take 0.614 and multiply it by 1,000 because then it will be a natural number. 0.614*1,000=614.

now you take 614/1,000 because that's what you multiplied it by and simplify it.

614/2 and 1,000/2=307/500 and this cannot be simplified any more than this because 307 is a prime number.

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2 years ago

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max2010maxim [7]

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Answer:

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Step-by-step explanation:

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2 years ago