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Art [367]
3 years ago
6

Simplify. 2³+4⋅8 please I beg you

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0
2^3=2*2*2
2*2*2+4*8
8+32
=> 40
svp [43]3 years ago
5 0
40 im sure kthx byellolnignog
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The number of mosquitoes at the beach has increased by 50% every year since 2012. In 2012, there were 2,500 mosquitoes. How many
xxTIMURxx [149]

Answer:

Step-by-step explanation:

2012 = 2500

2500 x .50 = 1250

2500 + 1250

2013 = 3750

3750 x .50 =

3750 + 1875

2014 = 5625

5625 x .50 = 2812.5

5625 + 2812.5

2015= 8437.5

8437.5 x .50 = 4218.75

8437.5 + 4218.75

2016= 12656.25

12656.25 x .50 = 6328.125

12656.25 + 6328.125

2017= 18984.375

18984.375 x .50 = 9492.1875

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3 years ago
Find the limit, if it exists, or type dne if it does not exist.
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\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
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Step-by-step explanation:

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