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Contact [7]
3 years ago
14

Don’t understand this help Hehehhe

Mathematics
2 answers:
Alexxandr [17]3 years ago
6 0

Answer:

5 × 5 × 5

Step-by-step explanation:

expanded basically means broken down... since the exponent is three, you have to multiply 5 three times

elena-14-01-66 [18.8K]3 years ago
4 0

125

Step-by-step explanation:

5×5×5

25×5

125

this is the correct answet

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Factor completely: (4c - x)^2 - (2c + 3x)^2
azamat

Answer:

Graph for (4*​2.99792e+08-​x)^​2-​(2*​2.99792e+08+​3*​x)^​2

More info

How to solve your problem

(4−)2−1(2+3)2

(4c−x)2−1(2c+3x)2(4c-x)^{2}-1(2c+3x)^{2}(4c−x)2−1(2c+3x)2

Simplify

1

Expand the square

(4−)2−1(2+3)2

(4c−x)2−1(2c+3x)2\left(4c-x\right)^{2}-1(2c+3x)^{2}(4c−x)2−1(2c+3x)2

(4−)(4−)−1(2+3)2

(4c−x)(4c−x)−1(2c+3x)2(4c-x)(4c-x)-1(2c+3x)^{2}(4c−x)(4c−x)−1(2c+3x)2

2

Distribute

(4−)(4−)−1(2+3)2

(4c−x)(4c−x)−1(2c+3x)2{\color{#c92786}{(4c-x)(4c-x)}}-1(2c+3x)^{2}(4c−x)(4c−x)−1(2c+3x)2

4(4−)−(4−)−1(2+3)2

4c(4c−x)−x(4c−x)−1(2c+3x)2{\color{#c92786}{4c(4c-x)-x(4c-x)}}-1(2c+3x)^{2}4c(4c−x)−x(4c−x)−1(2c+3x)2

3

Distribute

4(4−)−(4−)−1(2+3)2

4c(4c−x)−x(4c−x)−1(2c+3x)2{\color{#c92786}{4c(4c-x)}}-x(4c-x)-1(2c+3x)^{2}4c(4c−x)−x(4c−x)−1(2c+3x)2

162−4−(4−)−1(2+3)2

16c2−4cx−x(4c−x)−1(2c+3x)2{\color{#c92786}{16c^{2}-4cx}}-x(4c-x)-1(2c+3x)^{2}16c2−4cx−x(4c−x)−1(2c+3x)2

4

Distribute

162−4−(4−)−1(2+3)2

16c2−4cx−x(4c−x)−1(2c+3x)216c^{2}-4cx{\color{#c92786}{-x(4c-x)}}-1(2c+3x)^{2}16c2−4cx−x(4c−x)−1(2c+3x)2

162−4−4+2−1(2+3)2

16c2−4cx−4cx+x2−1(2c+3x)216c^{2}-4cx{\color{#c92786}{-4cx+x^{2}}}-1(2c+3x)^{2}16c2−4cx−4cx+x2−1(2c+3x)2

5

Combine like terms

162−4−4+2−1(2+3)2

16c2−4cx−4cx+x2−1(2c+3x)216c^{2}{\color{#c92786}{-4cx}}{\color{#c92786}{-4cx}}+x^{2}-1(2c+3x)^{2}16c2−4cx−4cx+x2−1(2c+3x)2

162−8+2−1(2+3)2

16c2−8cx+x2−1(2c+3x)216c^{2}{\color{#c92786}{-8cx}}+x^{2}-1(2c+3x)^{2}16c2−8cx+x2−1(2c+3x)2

6

Expand the square

162−8+2−1(2+3)2

16c2−8cx+x2−1(2c+3x)216c^{2}-8cx+x^{2}-1\left(2c+3x\right)^{2}16c2−8cx+x2−1(2c+3x)2

162−8+2−1(2+3)(2+3)

16c2−8cx+x2−1(2c+3x)(2c+3x)16c^{2}-8cx+x^{2}-1(2c+3x)(2c+3x)16c2−8cx+x2−1(2c+3x)(2c+3x)

7

Distribute

162−8+2−1(2+3)(2+3)

16c2−8cx+x2−1(2c+3x)(2c+3x)16c^{2}-8cx+x^{2}-1{\color{#c92786}{(2c+3x)(2c+3x)}}16c2−8cx+x2−1(2c+3x)(2c+3x)

162−8+2−1(2(2+3)+3(2+3))

16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{2c(2c+3x)+3x(2c+3x)}})16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))

8

Distribute

162−8+2−1(2(2+3)+3(2+3))

16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{2c(2c+3x)}}+3x(2c+3x))16c2−8cx+x2−1(2c(2c+3x)+3x(2c+3x))

162−8+2−1(42+6+3(2+3))

16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))16c^{2}-8cx+x^{2}-1({\color{#c92786}{4c^{2}+6cx}}+3x(2c+3x))16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))

9

Distribute

162−8+2−1(42+6+3(2+3))

16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))16c^{2}-8cx+x^{2}-1(4c^{2}+6cx+{\color{#c92786}{3x(2c+3x)}})16c2−8cx+x2−1(4c2+6cx+3x(2c+3x))

162−8+2−1(42+6+6+92)

16c2−8cx+x2−1(4c2+6cx+6cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+6cx+{\color{#c92786}{6cx+9x^{2}}})16c2−8cx+x2−1(4c2+6cx+6cx+9x2)

10

Combine like terms

162−8+2−1(42+6+6+92)

16c2−8cx+x2−1(4c2+6cx+6cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+{\color{#c92786}{6cx}}+{\color{#c92786}{6cx}}+9x^{2})16c2−8cx+x2−1(4c2+6cx+6cx+9x2)

162−8+2−1(42+12+92)

16c2−8cx+x2−1(4c2+12cx+9x2)16c^{2}-8cx+x^{2}-1(4c^{2}+{\color{#c92786}{12cx}}+9x^{2})16c2−8cx+x2−1(4c2+12cx+9x2)

11

Distribute

162−8+2−1(42+12+92)

16c2−8cx+x2−1(4c2+12cx+9x2)16c^{2}-8cx+x^{2}{\color{#c92786}{-1(4c^{2}+12cx+9x^{2})}}16c2−8cx+x2−1(4c2+12cx+9x2)

162−8+2−42−12−92

16c2−8cx+x2−4c2−12cx−9x216c^{2}-8cx+x^{2}{\color{#c92786}{-4c^{2}-12cx-9x^{2}}}16c2−8cx+x2−4c2−12cx−9x2

12

Combine like terms

162−8+2−42−12−92

16c2−8cx+x2−4c2−12cx−9x2{\color{#c92786}{16c^{2}}}-8cx+x^{2}{\color{#c92786}{-4c^{2}}}-12cx-9x^{2}16c2−8cx+x2−4c2−12cx−9x2

122−8+2−12−92

12c2−8cx+x2−12cx−9x2{\color{#c92786}{12c^{2}}}-8cx+x^{2}-12cx-9x^{2}12c2−8cx+x2−12cx−9x2

13

Combine like terms

122−8+2−12−92

12c2−8cx+x2−12cx−9x212c^{2}{\color{#c92786}{-8cx}}+x^{2}{\color{#c92786}{-12cx}}-9x^{2}12c2−8cx+x2−12cx−9x2

122−20+2−92

12c2−20cx+x2−9x212c^{2}{\color{#c92786}{-20cx}}+x^{2}-9x^{2}12c2−20cx+x2−9x2

14

Combine like terms

122−20+2−92

12c2−20cx+x2−9x212c^{2}-20cx+{\color{#c92786}{x^{2}}}{\color{#c92786}{-9x^{2}}}12c2−20cx+x2−9x2

122−20−82

Step-by-step explanation:

7 0
3 years ago
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Kobotan [32]

Answer:

35

Step-by-step explanation:

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Answer:

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3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
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