8x^2 -3 = 2
add 3 to each side
8x^2 = 5
divide by 8
x^2 =5/8
take the square root of each side
x = +- sqrt (5/8)
Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence

The desired probability is:

In which:

Then



Then:


0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377
The answer is D, tony would always be behind Robert.
Hello from MrBillDoesMath!
Answer:
12 m n^2
Discussion:
3m * 4 * n * n = => 3* 4 = 12
12 m * n * n => as n*n = n^2
12 m n^2
Thank you,
MrB
67 Animals. Hope this helps!