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2 years ago

12

1 1/3 • 5 3/4 pls helppp

2 answers:

zavuch27 [327]2 years ago

4 0

Answer:

The exact form would be 23/3

The mixed number form would be 7 2/3

Leni [432]2 years ago

3 0

Answer: I think its just 7.6

Step-by-step explanation:

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Explain why the following quotient is incorrect: <br><img src="https://tex.z-dn.net/?f=1%2C000%20%5Cdiv%205%20%3D%202%2C000" id=

vitfil [10]

Answer:

When you divide a positive number (such as 1,000) by a number greater than 1 (such as 5), the answer must be smaller than the number you started with. The answer must be smaller than 1,000. 2,000 is greater than 1,000, so it cannot be correct. The correct quotient is 1,000/5 = 200.

3 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

2 years ago

A circle has a diameter of 6 centimeters what is the approximate area of the circle

KiRa [710]

Answer:

28.26 $cm^{2}$

Step-by-step explanation:

The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.

The formula for the area of a circle is: π $r^{2}$

Plugging 3 into the radius, we have:

$3^{2}$ × π =

9 × π

We can round π to 3.14

9 × 3.14 = 28.26

7 0

2 years ago

Your Nike bill was $165.70. The tax is 30%. How much did<br> you<br> spend in total?

Rom4ik [11]

You spent $215.41 in total.

8 0

2 years ago

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Schach [20]

This is true. There is no question connected which is why there are no answers!

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2 years ago