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RoseWind [281]
3 years ago
12

Can somebody answer my question answer ASAP

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

what question

Step-by-step explanation:

I wanna help but I don't know what the question is sooo

mafiozo [28]3 years ago
6 0

Answer:

I would like to help.

Step-by-step explanation: But where is the question?

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The radius is longer than the diameter.<br><br> A) never true<br><br> B) always true
sweet [91]

Answer:

a) never true

Step-by-step explanation:

a radius is always half of a diameter

6 0
3 years ago
The LCD for 3/10, 20/25, and 18/75 is
Marizza181 [45]
The LCD for 3/10,20/25,and 18/75 is 150
3 0
3 years ago
Find the area of the figure.
11111nata11111 [884]

Answer:

180 sq.cm

Step-by-step explanation:

A = 10 x 10 + 16 x 5 x 1/2 x 2

A = 100 + 16 x 5

A = 100 + 80

A = 180 square cm

Hope that helps!

8 0
3 years ago
Read 2 more answers
Please help!!! will mark brainliest
faust18 [17]

Your answer is 7.

I subtracted 5 from 12 to find the missing number for KL that is 7.

Therefore, your answer is 7

6 0
2 years ago
Read 2 more answers
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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