Answer:hey must have the same denominator (the bottom value). If the denominators are already the same then it is just a matter of either adding or subtracting the numerators (the top value). If the denominators are different then a common denominator needs to be found.
Step-by-step explanation:
Find the are of the pool by dividing the volume by the depth:
1960 / 4 = 490
The pool is 490 square feet.
Area is found by multiplying the length by the width.
Let the width = X
We are told the length is 2.5X ( 2.5 times longer)
So we now have 2.5x * x = 490
2.5x * x = 2.5x^2
Now we have 2.5x^2 = 490
Divide both sides by 2.5:
x^2 = 490/2.5
x^2 = 196
find X by taking the square root of 196:
x = √196
x = 14
The width is 14 feet
The length is 2.5 * 14 = 35 feet
Answer:
14
Step-by-step explanation:
When there are 2 -, they both create a +. the brackets are removed and you get 4--10, which is equal to 4+10 which = 14
Number 6
Answer:
y = (c - ax)/b
Step-by-step explanation:
ax + by = c
by = c - ax
y = (c - ax)/b
<em>I answered number 5 in your last question.</em>
1a) False. A square is never a trapezoid. A trapezoid has only one pair of parallel sides while the other set of opposite sides are not parallel. Contrast this with a square which has 2 pairs of parallel opposite sides.
1b) False. A rhombus is only a rectangle when the figure is also a square. A square is essentially a rhombus and a rectangle at the same time. If you had a Venn Diagram, then the circle region "rectangle" and the circle region "rhombus" overlap to form the region for "square". If the statement said "sometimes" instead of "always", then the statement would be true.
1c) False. Any rhombus is a parallelogram. This can be proven by dividing up the rhombus into triangles, and then proving the triangles to be congruent (using SSS), then you use CPCTC to show that the alternate interior angles are congruent. Finally, this would lead to the pairs of opposite sides being parallel through the converse of the alternate interior angle theorem. Changing the "never" to "always" will make the original statement to be true. Keep in mind that not all parallelograms are a rhombus.
