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Tanzania [10]
3 years ago
7

What is the equation of the absolute function shown in the graph?

Mathematics
1 answer:
oee [108]3 years ago
6 0

Answer is <u>6|x+2|+2</u>

Please check the attached image of answer to clear the doubt.

<em>By </em><em>Benjemin</em><em> </em>☺️

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Please help me i need this grave !
Mice21 [21]

Answer:

C

Step-by-step explanation:

nvm i figured it out just do 7^2 + 8^2

5 0
3 years ago
What is -14n+1=rt-4n, solving for n
Korvikt [17]
Answer: n = -rt/10 + 1/10

Explanation: isolate the variable by dividing each side with the factors that don’t contain n, then isolate n to get this answer.

Hope this helps!
4 0
3 years ago
1. What is the value of the expression 3^-4?. a) -81. b) -12. c) -1/81. d) 1/81. 2. What is the value of the expression 1/4^3?.
hjlf

Answer:

1.

Option d is correct

2.

Option c is correct

3.

Option a is correct

4.

Option d is correct

5.

Option c is correct

Explanation:

Using exponent rule:

a^{-n} = \frac{1}{a^n}

1.

Given the expression:  

3^{-4}

Apply the exponent rules:

\frac{1}{3^4} = \frac{1}{81}

Therefore,  the value of the given expression is, \frac{1}{81}.

2.

To find the value of the expression \frac{1}{4^3}

then;

\frac{1}{4^3} = \frac{1}{64}

Therefore, the value of the given expression is, \frac{1}{64}.

3.

Find the the value of the expression \frac{2}{4^3}

then;

\frac{2}{4^3} = \frac{2}{64}

Simplify:

\frac{1}{32}

Therefore, the value of the given expression is, \frac{1}{32}.

4.

Given the expression:

K^{-3} = \frac{1}{27}

we can write this as:

K^{-3} = \frac{1}{3^3}

Apply the exponent rules:

K^{-3} = 3^{-3}

On comparing both sides we have;

K = 3

Therefore, the value of K is, 3

5.

Given the expression:

3^N= \frac{1}{81}

we can write this as:

3^N= \frac{1}{3^4}

Apply the exponent rules:

3^N = 3^{-4}

On comparing both sides we have;

N = 4

Therefore, the value of N is, -4

3 0
4 years ago
Read 2 more answers
Point M is the midpoint of PQ. The coordinates of P and M are given below.
Zepler [3.9K]

The coordinates of Q are (-1,6)

Further Explanation:

Given points are:

(x_m, y_m) = (5, -2)\\(x_p,y_p) = (11, -10)

The formula for mid-pint is:

(x_m, y_m) = (\frac{x_p+x_q}{2} , \frac{y_p+y_q}{2})\\From\ this\ we\ get\\x_m = \frac{x_p+x_q}{2}\\Putting\ values\\5 =\frac{11+x_q}{2}\\5*2 = 11+x_q\\10 = 11+x_q\\10-11 = x_q\\x_q = -1\\AND\\y_m = \frac{y_p+y_q}{2}\\-2 = \frac{-10+y_q}{2}\\-2*2 = -10+y_q\\-4 = -10+y_q\\-4+10 = y_q\\y_q = 6

The coordinates of Q are (-1,6)

Keywords: Coordinate geometry, mid-point

Learn more about mid-point at:

  • brainly.com/question/11018983
  • brainly.com/question/11175936

#LearnwithBrainly

7 0
3 years ago
What is the answer to the question ?????!!!!!!
inysia [295]
Here ya go have a great day!

6 0
3 years ago
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