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goldenfox [79]
3 years ago
9

Give an example of a 2x2 matrix whose determinant is 13.

Mathematics
2 answers:
tankabanditka [31]3 years ago
7 0

Answer:

\left[\begin{array}{ccc}1&0\\5&13\end{array}\right]

Step-by-step explanation:

If we have a matrix 2x2 as:

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]

The determinant is given by:

determinant = a*d - b*c

So, for find a matrix whose determinant is 13, we can choose the values of a, b and c at random and then solve the equation for d.

Then, for example if we replace the value of a by 1 the value of b by 0, and the value of c by 5, the equation for find d could be:

determinant = a*d - b*c

13 = 1*d - 0*5

Solving for d, we get:

13 = d -0

13 = d

So, one example of a 2x2 matrix whose determinant is 13 is the matrix with the form:

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]

Where a is 1, b is 0, c is 5 and d is 13. This matrix is:

\left[\begin{array}{ccc}1&0\\5&13\end{array}\right]

elixir [45]3 years ago
5 0
<span>If all your entries are integers, the determinant is also an integer. 
</span>For this problem, 1        0
                             0        13

For this question, you should just fix  3 values and make the 4th value an unknown and solve it.
I hope my answer helped you somehow.


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Anuta_ua [19.1K]

Answer:

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A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,
Alika [10]

The population of the moose after 12 years is 7692

Step-by-step explanation:

The form of the exponential growth function is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth factor

The table:

→  x  :  y

→  0  :  40

→  1   :  62

→  2  :  96

→  3  :  149

→  4  :  231

To find the value of a , b in the equation use the data in the table

∵ At x = 0 , y = 40

- Substitute them in the form of the equation above

∵ 40=a(b)^{0}

- Remember any number to the power of zero is 1 (except 0)

∴ 40 = a(1)

∴ a = 40

- Substitute the value of a in the equation

∴ y=40(b)^{x}

∵ At x = 1 , y = 62

- Substitute them in the form of the equation above

∵ 62=40(b)^{1}

∴ 62 = 40 b

- Divide both sides by 40

∴ 1.55 ≅ b

∴ The growth factor is about 1.55

- Substitute its value in the equation

∴ The equation of the population is y=40(1.55)^{x}

To find the population of moose after 12 years substitute x by 12 in the equation

∵ y=40(1.55)^{12}

∴ y ≅ 7692

The population of the moose after 12 years is 7692

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

7 0
3 years ago
What is all of this <br> Identify ALL sets of parallel and perpendicular lines in this image.
Tamiku [17]

<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!

<u>Perpendicular lines</u> intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!

Sets of parallel lines:

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Sets of perpendicular lines:

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5 0
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The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 269 day
fenix001 [56]

Answer:

a) 279 b)254

Step-by-step explanation:

Mean = 269 days

standard deviation = 8 days

let n be the pregnancy lenght.  

using normal distribution formula

z = (n – mean)/ standard deviation

n = z * standard deviation + mean

Now, z values for the top 12% has to be found using a z table.

The top 12% means 88% of area under the curve. In this case z = 1,176

n = 1,176 * 8 + 269

n = 278.4 = 279

The bottom 3% means 97% of area under the curve. In this case z = -1,882

n = -1,882 * 8 + 269

n = 253.94 = 254

6 0
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