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abruzzese [7]
3 years ago
5

THIS IS MY LAST QUESTION please help i’ll love y forever

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Step-by-step explanation:

Total ratio of flowers in Ben's garden =1+4=5

Total ratio of flowers in Ina's garden =2+5=7

No of flowers in Ben's garden 4/5 x=40

4x=200

divide through by 4

x=50

therefore , no of roses in Ben's garden =50 -40=10 roses.

2.) Ben's garden has 50 tulips and roses

3.) 2x/7=40

2x=280

divide through by 2

x=140 flowers in total

4.) No of roses =5/7×140 =100 roses in Ina's garden

5.) Ina's garden has 140 flowers

6.)Total number of tulips in both garden =40+40=80

7.)total number of roses =100+10 =110 roses

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Rapheal paid $624 for a camera during a 60% off sale. What was the cameras regular rice?
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$1040.00
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Raphael paid $624

624/.60= 1040.00
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3 years ago
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Answer:

1; -11+ 26 =15

2: 2- (-3) =5

3: 10+ (-4) = 7

4: 11 + -8 =3

5: -2 + 3 =1

6:  8 - 12 = -4

Step-by-step explanation:

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5 0
3 years ago
15+0.5x=25+0.25x please show how
sveticcg [70]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x= 40

8 0
3 years ago
Read 2 more answers
2. Ms. De Los Santos bought 5 3/7 gallons of ice cream for the 6th grade Wakanda Day celebration. If each scholar is served 1/16
nikdorinn [45]
So we convert both to improper fractions.
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3 years ago
Solve square root of x + square root of x+2 = 2
andrew-mc [135]

The value of x is \frac{1}{4}

Step-by-step explanation:

Given:

\sqrt{x} +  \sqrt{x + 2} = 2

Rearranging the radical on left side,

\sqrt{x + 2} = 2 - \sqrt{x}

Power on both sides,

(\sqrt{x + 2})^{2}  = (2 - \sqrt{x})^{2}

Simplifying the left,

x + 2 = (2 - \sqrt{x} )^{2}

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

=  > x + 2 =  {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}

Now calculating its powers,

=  > x + 2 = 4 - 4\sqrt{x} + x

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

=  > 4 \sqrt{x} = 4 + x - x - 2

Now the +x and -x will be cancelled,

=  > 4 \sqrt{x} = 4 - 2

=  > 4 \sqrt{x} = 2

Bringing 4 to the right side, it becomes the denominator,

=  >  \sqrt{x} =  \frac{2}{4}

=  >  \sqrt{x} =  \frac{1}{4}

Now powering both sides,

=  > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}

=  > x =  \frac{1}{4}

4 0
3 years ago
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