Find the value of y.y^2=169

Factor the perfect-square trinomial in y = (x2 + 2x + 1) − 1− 1.<br> y = (x + <br> )2 − 1 −1

dolphi86 [110]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

$y = ( {x}^{2} + 2x + 1) - 1$

$y = ({x + 1})^{2} - 1$

$y = ({x + 1})^{2} - ({1})^{2}$

We're done now but I have something to tell...

##############################

Hint :

${a}^{2} - {b}^{2} = (a + b)(a - b)$

##############################

$y = ( \: (x + 1) + 1)( \: (x + 1) - 1) \\$

$y = (x + 2)(x)$

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through the point (3,5) and is perpendicular to the line y=3.

3241004551 [841]

Answer:

x = 3

Step-by-step explanation:

y = 3 is the equation of a horizontal line parallel to the x- axis.

A line perpendicular to it must therefore be a vertical line parallel to the y- axis with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (3, 5) with x- coordinate 3 , thus

x = 3 ← equation of perpendicular line

6 0

3 years ago

Jim provides photos for two online sites: site A and site B. Site A pays $0.85 for every photo Jim provides. The amount in dolla

hram777 [196]

Answer:

Hello! I think the answer is D: $2.25. Please correct me if i'm wrong.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Mr. Mole left his burrow and started digging his way down at a constant rate.

Art [367]

Mr. Mole's burrow was at an altitude of 6 meters below the ground.

Step-by-step explanation:

Step 1:

We need to determine the distance that Mr. Mole covers in a single minute.

To do that we divide the difference in values of altitude by the difference in the time periods.

For the first case, Mr. Mole had traveled -18 meters in 5 minutes.

We also have, he traveled -25.2 meters in 8 minutes.

Step 2:

The distance he covered in 1 minute $= \frac{-25.2-(-18)}{8-5} = \frac{-25.2+18}{3},$

$\frac{-25.2+18}{3} = \frac{-7.2}{3} = -2.4.$

So with every minute, Mr. Mole digs down an additional 2.4 meters below the surface.

To determine where Mr. Mole's burrow is we subtract the distance traveled in 5 minutes from -18.

The altitude of Mr. Mole's burrow $= -18 - 5(-2.4) = -18+12 = -6.$

So Mr. Mole's burrow was at an altitude of 6 meters below the ground i.e. -6 meters.

5 0

3 years ago

Read 2 more answers

Q5 Q9.) Let theta be an angle in standard position. Name the quadrant in which theta lies

Juliette [100K]

Sine is positive while cotangent is negative. So this must mean cosine is negative since cos/sin = cot. In other words, cotangent is the ratio of cosine over sine.

Because cosine is negative and sine is positive, this places theta in quadrant 2
This is where x < 0 and y > 0. Recall that on the unit circle, x = cos(theta) and y = sin(theta).

The answer is choice B) quadrant II

7 0

3 years ago

Read 2 more answers