Question

What is the equation in slope-intercept form of a line parallel to y=−2x+5 and passes through the point (4, 0)?

Answer 1

Parallel lines have the same slope

The equation of the line is: $y = -2x+8$

The equation is given as:

$y = -2x + 5$

The slope intercept form of an equation is:

$y = mx + b$

Where:

$m \to slope$

By comparison,

$m = -2$

The line is said to be parallel to $y = -2x + 5$.

This means that the line has a slope of $m = -2$

The equation of the line is then calculated as:

$y = m(x - x_1) + y_1$

Where:

$(x_1,y_1) = (4,0)$

So, we have:

$y = m(x - x_1) + y_1$

Substitute values for m, x1 and y1

$y = -2(x - 4) + 0$

$y = -2(x - 4)$

Open brackets

$y = -2x+8$

Hence, the equation of the line is: $y = -2x+8$

See attachment for the graphs of $y = -2x+8$ and $y = -2x + 5$

Read more about equations of parallel lines at:

brainly.com/question/402319