The lines shown below are parallel. If the green line has a slope of -3/7, what is

The stemplot below represents the number of bite-size snacks grabbed by 37 students in an activity for a statistics class.

Simora [160]

Answer:

The distribution of the number of snacks grabbed is skewed right with a center around 18 and varies from 12 to 45. There are possible outliers at 38, 42, and 45.

Step-by-step explanation:

First, we can see if the graph is symmetric. A symmetric graph is even on both sides of the center. As there are a lot more students that grabbed a small number of snacks, and the data is not even around the center (which is somewhere around 20 or 30 snacks). This means that the graph is not symmetric, making the second answer incorrect.

Next, we can check if the graph is skewed right or left. If the left of the graph represents a smaller amount of snacks and the right of it represents a higher number of snacks, we can see that most of the data is on the left of the graph. There are a few values to the right, but the overwhelming amount of data is on the left, making the distribution skewed to the right. This keeps the first and last answers possible

Moreover, we can find the center of the distribution. This is generally equal to the median, which is 18, so the center is around 18

After that, we can see what the values vary from. The lowest tens value is 1, and the lowest ones value in that is 2, making the lowest value 12. Similarly, the highest tens value is 4, and the highest ones value there is 5, making the range 12 to 45. This leaves the last answer, but we can check the outliers to make sure.

With the data, we can calculate the first quartile to be 15, the third quartile to be 21.5, and the interquartile range to be 21.5-15 = 6.75 . If a number is less than Q₁ - 1.5 * IQR or greater than Q₃ + 1.5 * IQR, it is a potential outlier. Applying that here, the lower bound for non-outliers is 15 - 6.5 * 1.5 = 5.25, and the upper bound if 21 + 6.5 * 1.5 = 30.75. No values are less than 5.25, but there are four values greater than 30.75 in 32, 38, 42, and 45. There are possible outliers at 38, 42, and 45, matching up with the last answer.

4 0

3 years ago

Rewrite the radical expression as an exponential expression, and then simplify.

sergij07 [2.7K]

Answer:

Answer is C

Step-by-step explanation:

just did the test

8 0

3 years ago

Read 2 more answers

If c, m, and n are integers, which of the following are NOT possible values of m and n for the equation below? (Equation in pic)

kakasveta [241]

Answer: C. m = -2; n = -2

have:

x² + 4x + c = (x + m)(x + n)

⇔ x² + 4x + c = x² + (m + n)x + mn

⇒ m + n = 4

mn = c

=> M=-2, n=-2 arent possible

Step-by-step explanation:

6 0

3 years ago

The function f(x) = −x2 + 18x − 72 models the daily profit, in dollars, a gym makes for selling memberships, where x is the numb

Natalija [7]

Answer:

Step-by-step explanation:

The way to do this so as to streamline both the vertex and finding the zeros is to complete the square. That method will provide us with the vertex, and then we can continue on to factor from that form to find the zeros. Completing the square requires us to set the quadratic equal to 0 then move over the constant, giving us

$-x^2+18x=72$ The leading coefficient HAS to be a positive 1; ours is negative 1 so we factor out the negative to get:

$-(x^2-18x)=72$ Now we're ready to complete the square.

Take half the linear term, square it, and add it to both sides. Our linear term is 18 (from -18x; don't worry about the negative because squaring it makes it positive anyway). Half of 18 is 9, and 9 squared is 81.

BUT on the left we have that -1 sitting out front that refuses to be ignored. What we actually added on to the left side, inside the parenthesis, is -1(81) which is -81. -81 is what we add to the right since that turns out to be what we added to the left:

$-(x^2-18x+81)=72-81$ and we clean that up.

The reason we complete the square is because when we simplify the left side, we end up with a perfect square binomial found from taking the square root of x-squared, the first sign we come to, then the square root of 81:

$-(x-9)^2=-9$ . Move the constant back over to get

$-(x-9)^2+9=y$ telling us that the vertex is (9, 9). In the context of the problem that means that the gym sells on average 9 memberships a day and the profit it makes on average per day is $9.

To factor, we will go back one step to

$-(x-9)^2=-9$ and begin by dividing both sides by -1 to get

$(x-9)^2=9$ and undo the squaring by taking the square root of both sides to get

x - 9 = ±3 so

x = 9 + 3 and

x = 9 - 3 so

x = 6 and 12

Those are the zeros. This means that if they sell either 6 or 12 memberships they have a 0 profit. That may sound strange, but in business it does often work like that...selling too many of something makes your company lose money (this is often due to the cost required by you to produce or manufacture the product).

8 0

3 years ago

CAN YALL HELO ME ON LETTER (B) PLEASE

Kruka [31]

Step-by-step explanation:

b.

g(-3) = (-3)²+1 = 9+1 = 10

7 0

3 years ago