Answer:
Yes
Step-by-step explanation:
Given,
Population mean Z = 600
Sample mean, µ = 586.50
Size of the sample, n = 10
Standard deviation, σ = 26.77
The testing hypothesis is,
Null hypothesis = µ<600
Alternative hypothesis = µ≥600
The test statistics is the calculated value of Z,
(Z- µ)/(σ/√n)
= (600-586.50)/(26.77/√10)
= (13.5*3.1623)/26.77
= 42.691/26.77
= 1.5947
And at 5% level of significance, the table value of Z = 1.644
Here, calculated Z<Table value of Z, so we accept the null hypothesis.
So, the null hypothesis is accepted. The mean value of the laptop is less than 600.
Mr Wellborn arrives at work at 7:50 am. If you take 60 minutes away from 8:40 its 7:40 but take away 10 minutes and its 7:50.
The proposal for the price for a number of shirts given by the four companies can be analyzed graphically, given that each price list gives a straight line, and the result presented using a piecewise function approach as follows:

<h3>What is a piecewise function?</h3>
A piecewise defined function is one that has other sub functions which are applied over different intervals of the domain.
The given table of values and equation are plotted on a graph using MS Excel
From the graph, and the table created, we have:
When the number of shirts on order is less than 40, the least expensive is Easy Calculation shirts
When the number of shirts are more than 40 but less than 80, the least expensive proposal is given by Shirtee
When the number of shirts to be ordered is more than 80, the company that gives the least expensive proposal is T-Shirts R Us
The selection table is presented as follows:

Learn more about piecewise defined functions here:
brainly.com/question/18499561
#SPJ1
Answer: 
Step-by-step explanation:
The confidence interval estimate for the population mean is given by :-
, where
is the sample mean and ME is the margin of error.
Given : Sample mean: 
The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : 
Now, the confidence interval estimate for the population mean will be :-

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution = 