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Irina-Kira [14]
3 years ago
9

Based on the limited amount of available student parking spaces on the GSU campus, students are being encouraged to ride their b

ikes (when appropriate). The administration conducted a survey to determine the proportion of students who ride a bike to campus. Of the 120 students surveyed 5 ride a bike to campus. Which of the following is a reason the administration should not calculate a confidence interval to estimate the proportion of all students who ride a bike to campus? Check all that apply. The sample needs to be random but we don’t know if it is. The actual count of bike riders is too small. The actual count of those who do not ride a bike to campus is too small. n * ^ p is not greater than 10 . n *( 1 − ^ p )is not greater than 10 .
Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

1

Step-by-step explanation:

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A carpenter wants to build a rectangular box with square sides in which to put round things. the material for the bottom costs $
alexira [117]

Answer:1.627\times 1.627\times 1.88\ ft^3

Step-by-step explanation:

Given

Suppose side face have a dimension of l\times l

and width of h

volume V=l^2\cdot h

h=\frac{V}{l^2}

volume V=5 ft^3

Area of side wall is A_s=l^2

Area of top Wall A_t=l\times h

Area of bottom A_b=l\times h

Cost of bottom wall c_b=20\times l\times h=20lh

Cost of top wall c_t=50\times l\times h=50lh

Cost of side walls c_s=4\times l^2\times 10=40l^2

total cost C=c_s+c_t+c_b=20lh+50lh+40l^2

C=70lh+40l^2

C=70\times l\times \frac{5}{l^2}+40l^2

differentiate C w.r.t l to get minima or maxima

\frac{\mathrm{d} C}{\mathrm{d} l}=0

-\frac{350}{l}+80l^2=0

l^3=\frac{350}{80}

l=1.627 ft

h=\frac{5}{2.648}

h=1.88 ft

Dimension of Box is 1.627\times 1.627\times 1.88\ ft^3

5 0
3 years ago
Liam had $250. Then, he and his classmates bought a present for their teacher, evenly splitting the $p cost among the 24 of them
lord [1]

Answer:

The answer is 600-p/24

Step-by-step explanation:

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3 years ago
What percent of 86 is 14
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the anwser is 614.29

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3 years ago
Read 2 more answers
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
tester [92]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<u><em>A) If the length of a rectangle was tripled, but the  width did not change?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<u><em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em></u>

Perimeter

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

Area

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

5 0
3 years ago
The sum of three consecutive numbers is 45. What is the<br> largest of these numbers?
Arturiano [62]

Answer:

14,15,16

Step-by-step explanation:

a+a+1 +a+2=45

3a+3 =45

3a=45-3

3a=42

a=42:3 =14(the first number

14+1=15 (the second number

14+2=16 (the third number, the largest number

8 0
3 years ago
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