We are given original equation:
We need to find the enter and radius of a circle using the completing the square method.
The steps are as following :
Step 1 [original equation]: x^2 − 10x + y^2 + 12y = 20 .
Step 2 [group like terms]: (x^2 − 10x) + (y^2 + 12y) = 20
Step 3 [complete the quadratics]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 20 + (25 + 36).
Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.
Step 5 [factor each quadratic]: (x − 5)^2 + (y + 6)^2 = 8^2
Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.
<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>
Combine the like terms
-x-x^2+7
Answer:
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Step-by-step explanation:
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Answer:
The value of x = 2
Step-by-step explanation:
Given the equation
- Expand 12(x-2) = 12x - 24
- Expand 1/2(x+6) = 1/2x + 3
so the equation becomes
simplifying
multiplying both sides by 2
subtracting x from both sides
divide both sides by 29
simplifying
Therefore, the value of x = 2