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Ad libitum [116K]
3 years ago
11

Write a polynomial function of least degree with integral coefficients that has the

Mathematics
1 answer:
frutty [35]3 years ago
6 0

A polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Given

Given zeros are 3i, -1  and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)

Now we multiply it to get the polynomial

x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Learn more : brainly.com/question/7619478

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Answer:

See below

Step-by-step explanation:

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         7 - 9                                - [ -12/5 ]

         -2                                         2.4

23.  11x - 11   x = -11         24.  (2/9)x - (9/2)   x= 9

       - 121 - 11                           (2/9)(9) - (9/2)

         -132                                  2 - (9/2)  ( 2 can be shown as 4/2)

                                                      (4/2) - (9/2)

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