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labwork [276]
2 years ago
11

Assign total_owls with the sum of num_owls_A and num_owls_B.

Computers and Technology
1 answer:
zavuch27 [327]2 years ago
8 0

To debug a code, means that we locate and fix the errors in a code.

The issue with your code is that:

<em>You did not convert num_owls_A and num_owls_B to integers, when adding them together.</em>

The fix to this is that:

<em>You need to convert num_owls_A and num_owls_B to integers, when adding them together.</em>

The fix is as follows:

<em>total_owls = int(num_owls_A) + int(num_owls_B)</em>

The updated code is as follows:

<em>total_owls = 0 </em>

<em>num_owls_A = input() </em>

<em>num_owls_B = input() </em>

<em>total_owls = int(num_owls_A) + int(num_owls_B) </em>

<em>print('Number of owls:', total_owls)</em>

<em />

<em>The above code will perform addition operations for all inputs</em>

Read more about Python programs at:

brainly.com/question/13246781

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Question: 4/8
Gemiola [76]

The generated test cases for the function assuming another developer coded the function is given below in a C++ program.

<h3>THE CODE</h3>

#include <iostream>  

#include <iomanip>

#include <string>

using namespace std;

// define the data type "triangletype" with {values}

enum triangleType { scalene, isosceles, equilateral, noTriangle };

// Prototype function which returns the position of triangleType{value}

// Example: Scalene = 0, isosceles = 1, etc. These are zero indexed.

triangleType triangleShape(double a, double b, double c);

// Prototype function which takes the integer value of the

// triangle type and outputs the name of triangle

string shapeAnswer(int value);

int main() {

   double inputA;

   double inputB;

   double inputC;

   cout << "To determine whether a triangle is either:" << endl;

   cout << setw(50) << " - Scalene" << endl; // Unequal in length

   cout << setw(52) << " - Isosceles" << endl; // Two sides equal length

   cout << setw(54) << " - Equilateral" << endl; // All sides equal

   cout << setw(57) << " - Not a triangle" << endl;

   cout << "Enter side A: ";

   cin >> inputA;

   cout << "Enter side B: ";

   cin >> inputB;

  cout << "Enter side C: ";

   cin >> inputC;

   cout << "The triangle is " << shapeAnswer(triangleShape(inputA, inputB, inputC)) << endl;

}

triangleType triangleShape(double a, double b, double c) {

   triangleType answer;

   if ( c >= (a + b) || b >= (a + c) || a >= (b + c) ) {

       answer = noTriangle;

   }

   else if (a == b && b == c) {

       answer = equilateral;

   }

   // Test the 3 options for Isosceles equality

   else if ( (a == b) && (a != c) || (b == c) && (b != a) || (a == c) && (a != b) ) {

       answer = isosceles;

   }

   else {

       answer = scalene;

   }

   return answer;

}

string shapeAnswer(int value) {

   string answer;

  switch (value) {

   case 0:

       answer = "Scalene";

       break;

   case 1:

       answer = "Isosceles";

       break;

   case 2:

       answer = "Equilateral";

       break;

   case 3:

       answer = "Not a triangle";

       break;

   default:

       break;

   }

   return answer;

}

Read more about C++ programs here:

brainly.com/question/20339175

#SPJ1

8 0
1 year ago
Select the correct answer.
Mekhanik [1.2K]
The best answer is A
5 0
2 years ago
Read 2 more answers
Name the box where the name of the first cell of the selected range appears?
sergey [27]

Answer:

Name box

Explanation:

From the picture, the name box is at the top left corner with B1 written inside, here B1 is written because it is the active cell at the time which also happens to be the first cell of the selected range. The name box can be used to easily create a named ranges rather Than having to draw the mouse over a group of cells. It also helps to know which cell is the current active cell as the cell address in the name box is the active cell at any point in time.

4 0
3 years ago
What would be the results of the following code? int[] x = { 55, 33, 88, 22, 99, 11, 44, 66, 77 }; int a = 10; if(x[2] &gt; x[5]
Nezavi [6.7K]

Answer:

The answer is "Option A".

Explanation:

In the given code an integer array "x" is defined, that stores some elements and another integer variable "a" is declared, that holds a value that is "10". In this code a conditional statement is defined, which checks array element value, in if block element of array that position is 2 is greater then the element of array that position is 5.if this condition is true, so variable a value is change that is equal to 5. In else block if the above condition is not true so the value of a variable is equal to 8, and another options is wrong that can be described as follows:

  • In option B, The given condition is not false, that's why it is not correct.
  • In option C, The value of variable a is changed when condition is true or false, that's why it is not correct.
  • In option D, It is wrong because we can compare array elements.

6 0
3 years ago
Write a Java program that reads two numbers from the console. Based on the example in the textbook, write five methods (min, max
makvit [3.9K]

Answer:

import java.util.Scanner;

public class num6 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter first number");

       int a = in.nextInt();

       System.out.println("Enter second number");

       int b = in.nextInt();

       //Calling the methods inside the output statement

       System.out.println("Min is "+min(a,b));

       System.out.println("Max is "+ max(a,b));

       System.out.println("Sum is "+sum(a,b));

       System.out.println("Product is "+product(a,b));

       System.out.println("Absolute difference is "+difference(a,b));

   }

   //Min Method

   static int min(int a, int b){

       if (a<b){

           return a;

       }

       else {

           return b;

       }

   }

   //Max Method

   static int max(int a, int b){

       if (a>b){

           return a;

       }

       else {

           return b;

       }

   }

   //Sum Method

   static int sum(int a, int b){

       return a+b;

   }

   //Diference Method

   static int difference(int a, int b){

       int diff = Math.abs(a-b);

       return diff;

   }

   //Product Method

   static int product(int a, int b){

       int prod = a*b;

       return prod;

   }

}

Explanation:

  • Using Java programming language
  • Use the scanner class to prompt and receive two values from the user (integers a and b)
  • Create the four methods as required (Please see the comments in the code)
  • In the difference method use Math.abs() to get the absolute value of the subtraction ensuring that you get a positive number returned
4 0
2 years ago
Read 2 more answers
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