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podryga [215]
3 years ago
8

How are the step by step math problem suppose to be for this math problem (-2-8)^2?

Mathematics
1 answer:
Sidana [21]3 years ago
6 0

Answer:

the answer is 100

Step-by-step explanation:

(-2-8)^2

(-2-8)(-2-8)

-2(-2-8)-8(-2-8)

4+16+16+64

20+80

100

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Find the components of the vertical force Bold Upper Fequalsleft angle 0 comma negative 8 right anglein the directions parallel
nydimaria [60]

Answer with Step-by-step explanation:

We are given that

F=<0,-8>=0i-8j=-8j

\theta=\frac{\pi}{3}

The component of force is divided into two direction

1.Along the plane

2.Perpendicular to the plane

1.The vector parallel to the plane will be=r=cos\frac{\pi}{3}i-sin\frac{\pi}{3}j=\frac{1}{2}i-\frac{\sqrt 3}{2}j

By using cos\frac{\pi}{3}=\frac{1}{2},sin\frac{\pi}{3}=\frac{\sqrt 3}{2}

Force along the plane will be=\mid F_x\mid=F\cdot r

Force along the plane will be =\mid F_x\mid=F\cdot (\frac{1}{2}i-\frac{\sqrt 3}{2}j)=-8j\cdot(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=8\times \frac{\sqrt 3}{2}=4\sqrt 3N

By using i\cdot i=j\cdoty j=k\cdot k=1,i\cdot j=j\cdot k=k\cdot i=j\cdot i=k\cdot j=i\cdot k=0

Therefore, force along the plane=\mid F_x\mid(\frac{1}{2}i-\frac{\sqrt 3}{2}j)=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)

2.The vector perpendicular to the plane=r=-sin\frac{\pi}{3}-cos\frac{\pi}{3}=-\frac{\sqrt 3}{2}i-\frac{1}{2}j

The force perpendicular to the plane=\mid F_y\mid=F\cdot r=-8j(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

The force perpendicular to the plane=4N

Therefore, F_y=4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=F_x+F_y=4\sqrt 3(\frac{1}{2}i-\frac{\sqrt 3}{2}j)+4(-\frac{\sqrt 3}{2}i-\frac{1}{2}j)

Sum of two component of force=2\sqrt 3i-6j-2\sqrt3 i-2j=-8j

Hence,sum of two component of forces=Total force.

6 0
3 years ago
Raj’s farmhouse is 1245km away from hiswarehouse. Daily he drivesa certain distance and then his friend Rohantakes aturn to driv
mariarad [96]

Answer:

Step-by-step explanation:

Subtract the distance driven by Rohan from the total distance

Distance driven by Raj = 1245 - 412

                                     = 833 km

8 0
3 years ago
A12.5 ft ladder is leaning against the side of a house. If the ladder is resting 12 feet off the ground, how far is the ladder f
Elanso [62]

Answer:

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Step-by-step explanation:

This can be calculatdd by applyinthe g Pythagorean theorem

a^2 + b^2= c^2

12^2 + x^2= 12.5^2

144+ x^2= 156.25

x^2= 156.25-144

x^2= 12.25

x= √12.25

x= 3.5

Hence the distance between the ladder and the house is 3.5 ft

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alisha [4.7K]

Answer:

2

Step-by-step explanation:

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